√363 - 3√27 simplify the radical expression. Show all your steps please :)

A cuboid in which the sum of its dimensions is 9 cm., then the sum of its edge lengths - cm. (18 or 27 or 36 or 45)

ser-zykov [4K]

The number of sides or edges on a cuboid are twelve, and the sum of the

edges is the sum of the twelve edges.

The sum of the edge lengths = 36 cm

Reasons:

The given parameters are;

The sum of the dimension of the cuboid = 9 cm

Required:

The value sum of the dimension of the edges the cuboid.

Solution:

The dimensions of a cuboid are; Length, l, width, w, and height, h

We get;

l + w + h = 9

The number of times that each dimension appear = 4 times

4 edges with the same length as the height, h

4 edges with the same length as the width, w

4 edges with the same length as the length, l

The sum of the edge lengths is therefore; Sum Edges = 4·l + 4·w + 4·h

Which gives;

Sum Edges = 4·l + 4·w + 4·h = 4 × (l + w + h) = 4 × 9 = 36

The sum of the edge lengths = 36 cm.

Learn more here:

brainly.com/question/12978944

5 0

2 years ago

What is the length of side A, in centimeters, on the enlarged trapezoid? 4 6 12 20

Kazeer [188]

Answer:

C

Step-by-step explanation:

given the fact that the other side measures all multiply by 4 when they are enlarged in the second shape, we know that the scale factor is 4. 3 enlarged by a scale factor of 4 = 12

4 0

3 years ago

Read 2 more answers

(t,-3) and (2,6); Slope = -1

tangare [24]

-1= $\frac{Δy}{Δx}$
-1= $\frac{6-(-3)}{2-t}$
t-2=9
t=11

4 0

3 years ago

Equation 2(4x − 11) = 10.

dedylja [7]

Since you didn't provide instructions, I am going to assune you are being asked to solve for x. To do this, just distribute and simplify.

2(4x-11)=10
Distribute the 2 to the expression (4x-11)
8x-22=10
Add 22 on both sides
8x=32
Divide by 8 on both sides
x=4

~I hope this helps!~

4 0

3 years ago

One of the earliest applications of the Poisson distribution was in analyzing incoming calls to a telephone switchboard. Analyst

grandymaker [24]

Answer:

(a) P (X = 0) = 0.0498.

(b) P (X > 5) = 0.084.

(c) P (X = 3) = 0.09.

(d) P (X ≤ 1) = 0.5578

Step-by-step explanation:

Let X = number of telephone calls.

The average number of calls per minute is, λ = 3.0.

The random variable X follows a Poisson distribution with parameter λ = 3.0.

The probability mass function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,3...$

(a)

Compute the probability of X = 0 as follows:

$P(X=0)=\frac{e^{-3}3^{0}}{0!}=\frac{0.0498\times1}{1}=0.0498$

Thus, the probability that there will be no calls during a one-minute interval is 0.0498.

(b)

If the operator is unable to handle the calls in any given minute, then this implies that the operator receives more than 5 calls in a minute.

Compute the probability of X > 5 as follows:

P (X > 5) = 1 - P (X ≤ 5)

$=1-\sum\limits^{5}_{x=0} { \frac{e^{-3}3^{x}}{x!}} \,\\=1-(0.0498+0.1494+0.2240+0.2240+0.1680+0.1008)\\=1-0.9160\\=0.084$

Thus, the probability that the operator will be unable to handle the calls in any one-minute period is 0.084.

(c)

The average number of calls in two minutes is, 2 × 3 = 6.

Compute the value of X = 3 as follows:

$P(X=3)=\frac{e^{-6}6^{3}}{3!}=\frac{0.0025\times216}{6}=0.09$

Thus, the probability that exactly three calls will arrive in a two-minute interval is 0.09.

(d)

The average number of calls in 30 seconds is, 3 ÷ 2 = 1.5.

Compute the probability of X ≤ 1 as follows:

P (X ≤ 1 ) = P (X = 0) + P (X = 1)

$=\frac{e^{-1.5}1.5^{0}}{0!}+\frac{e^{-1.5}1.5^{1}}{1!}\\=0.2231+0.3347\\=0.5578$

Thus, the probability that one or fewer calls will arrive in a 30-second interval is 0.5578.

5 0

3 years ago