Answer:
if you would stan LOONA you would get all A's):
<u>Let's consider the facts at hand</u>:
- By Vertical Angle Theorem ⇒ ∠BCE = ∠DCF
- ∠BEC = ∠DFC
- Sides BE = DF
<u>Based on the diagram, triangles BCE and triangles DCF are similar</u>
⇒ based on the Angle-Angle theorem
⇒ since ∠BCE = ∠DCF and ∠BEC = ∠DFC
⇒ the two triangles are similar
Hope that helps!
<em>Definitions of Theorem I used:</em>
- <u><em>Vertical Angle Theorem: </em></u><em>opposite angles of two intersecting lines must be equal</em>
- <u><em>Angle-Angle Theorem:</em></u><em> if two angles of both triangles are equal, then the given triangles must be similar</em>
<em />
They lie in the same plane is the answer ;)
Answer:
I'm pretty sure the answer is -a²b and 5a²b
Step-by-step explanation:
Step-by-step explanation:
<u>y</u> - <u>1</u> = <u>-</u><u>3</u>
x - 0 2
2y - 2 = -3x
2y = -3x + 2
