2 years ago

Can someone help me with this math problem

Mathematics

2 answers:

san4es73 [151]2 years ago

6 0

30 is the answer
i can help if need be

dexar [7]2 years ago

6 0

Add 3/10 to 6/10 to receive an answer of...
9/10!

You might be interested in

Determine the sum of the arithmetic series: 5+18 +31 +44 + ... 161.

Finger [1]

Answer:

1079

Step-by-step explanation:

Hello,

18-5 = 13

31-18=13

44-31=13

161=5+13*12

So we need to compute

$\displaystyle \sum_{k=0}^{k=12} \ {(5+13k)}\\\\=\sum_{k=0}^{k=12} \ {(5)} + 13\sum_{k=1}^{k=12} \ {(k)}\\\\=13*5+13*\dfrac{12*13}{2}\\\\=65+13*13*6\\\\=65+1014\\\\=1079$

Thanks

3 0

3 years ago

I need help with geometry

VLD [36.1K]

Answer:

180-71

=109

the last one

5 0

2 years ago

Please help me with this

Gelneren [198K]

345235235232352352353523523535

5 0

3 years ago

I really don’t understand this please help!!

Yuliya22 [10]

H=√d^2-w^2
=√146.4 1-92.16
=7.3 inches
the principle used here is pythagoras theorem
all the best.

6 0

2 years ago

The answer to the following q.

Katen [24]

Answer:

See below ~

Step-by-step explanation:

Given :

⇒ m∠1 = m∠2

⇒ HD = GF

=============================================================

To Prove :

<u />

============================================================

Solving :

⇒ m∠1 = m∠2 (Given)

⇒ HD = GF (Given)

⇒ ∠E = ∠E (Common angle)

⇒ ΔEHD ≅ ΔEGF (AAS congruence)

3 0

1 year ago

Read 2 more answers