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Volgvan
3 years ago
5

What would the distance between the ordered pairs (-2,3) and (4,-6) be?

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
7 0

Answer: 5.099

Step-by-step explanation:

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Finding Distance in the Coordinate Plane!
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It is B. the differences are added together

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What is the area of the triangle below?
stira [4]

Answer:

7.5 square units

Step-by-step explanation:

Base of the triangle = 5 units

Height of the triangle = 3 units

Area of the triangle

=  \frac{1}{2}  \times base \times height \\  \\  =  \frac{1}{2}  \times 5 \times 3 \\  \\  =  \frac{1}{2}  \times 15 \\  \\  = 7.5 \:  {units}^{2}

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Based on the figure below, what is the value of x?
oksano4ka [1.4K]

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x=9

Step-by-step explanation:

90(the angle)-30=60

60-15=45

45/5=9

<u>(5(9)+15)+30=90</u>

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2 years ago
Derek spends $8.50 a day on school breakfasts and lunches. How much does he spend on food in a school week? (Hint: there are 5 d
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Answer:

$42.50

Step-by-step explanation:

$8.50 x 5 days = $42.50

5 0
3 years ago
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A gas station stores its gasoline in a tank underground. The tank is a cylinder lying horizontally on its side. The radius is 5
atroni [7]

Answer:

The exact work required to pump all the gasoline to the surface of the ground is π × 5.094 × 10⁶ j

Step-by-step explanation:

Here, we note that volume of a slice is given by

Length × Width × Height

Length of slice = Length of cylinder = 15 ft

Since the slice height is Δy ft thick and located y ft above the center of the cylinder, then

Width of slice = 2 × √(r² - y²)

Where:

r = Radius of the cylinder =5 ft

∴ Width of slice = 2 × √(25 - y²)

∴Volume of slice = 15 ×2 × √(25 - y²)×Δy

Mass of slice then = 42 × 15 ×2 × √(25 - y²)×Δy = 1260 × √(25 - y²)×Δy

The force required to lift the slice is the weight of the slice, which is given by

32.2 × 1260 × √(25 - y²)×Δy = 40572 × √(25 - y²)×Δy N (Newtons)

The work done by the force is the product of the force and the distsnce through which the force acts.

Work done = 40752×(10-y) × √(25 - y²)×Δy

Therefore total work done is given by

W = \int\limits^5_{-5} {40752\times (10-y) \times \sqrt{ (25 - y^{2} )} } \, dy

 

= 5094000·π J = π × 5.094 × 10⁶ j

The exact work required to pump all the gasoline to the surface of the ground = π × 5.094 × 10⁶ j

6 0
3 years ago
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