Answer:
The measure of the angle JKG is:
m∠JKG = 56°
Step-by-step explanation:
<u>Given</u>
m∠JKG = 76-2x
m∠FHK = 6x-4
J is a midpoint of the segment FG and K is a midpoint of the segment GH.
<u>To determine</u>
m∠JKG = ?
Given that J is a midpoint of the segment FG and K is a midpoint of the segment GH. Thus, making two similar triangles, ΔJGK and ΔFGH
We know that two triangles are similar if the only difference is size. So, the angles remain the same.
so m∠JKG and m∠FHK are equal.
i.e.
m∠JKG = m∠FHK
substitute m∠JKG = 76-2x and m∠FHK = 6x-4
76-2x = 6x-4
6x+2x = 76 + 4
8x = 80
divide both sides by 8
8x/8 = 80/8
x = 10
Therefore, the value of x = 10
As
m∠JKG = 76-2x
substitute x = 10
m∠JKG = 76 - 2(10)
= 76 - 20
= 56°
Therefore, measure of the angle JKG is:
m∠JKG = 56°
Answer:
Step-by-step explanation:
The graph is symmetric with respect to the origin therefore it is on odd function. The graph is symmetric to the y- axis therefore it is an even function. The majority of functions are neither odd nor even, however, sine and tangent are odd functions and cosine is an even function.
X/2 = 3 (x= 3*2 = 6in)
6in = 30ft
Hope I become the brainliest answer
Answer:
Step-by-step explanation:
(simplify)
(Add 3 to both sides)
(simplify)
(Multiply both sides by p)
(Multiply both sides by 2)
(Divide both sides by 7)
Answer:
Step-by-step explanation:
1/3 (3x+12)
1/3×3x+1/3×12
x+4
