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kondaur [170]
3 years ago
15

Charles has been assigned several chores around the house he washed the supper dishes every fifth day, he takes out the trash ev

ery other day, and he vacuumes the house every seven days. How often does he have to do all three things on the same day?
Mathematics
1 answer:
ch4aika [34]3 years ago
5 0
This question is about the GREATEST COMMON FACTOR. 

Supper Dishes: 5      10         15         20       25           30          35 

Trash: 1        3           5          7             9          11      13            15         17         19      21       23       25          27           29           31        33         35

Vacuums the House: 7         14          21         28         35            42

He will have to do all three chores on the same day every 35 day.



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Factories 54m3n + 81m4n2 b) 15x2y3z + 25x3y2z + 35x2y2z​
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<u>Part a)</u>

Given the expression

54m^3n\:+\:81m^4n^2

Apply exponent rule:    a^{b+c}=a^ba^c

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn     ∵ m^4n^2=m^3mnn

Rewrite 81 as 3 · 27

Rewrite 54 as 2 · 27

                             =2\cdot \:27m^3n+3\cdot \:27m^3mnn

Factor out the common term:   27m³n

                              =27m^3n\left(2+3mn\right)      

Therefore,

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn=27m^3n\left(2+3mn\right)

<u>Part B)</u>

Given the expression

15x^2y^3z+25x^3y^2z+35x^2y^2z

Apply exponent rule:    a^{b+c}=a^ba^c

15x^2y^3z+25x^3y^2z+35x^2y^2z=15x^2y^2yz+25x^2xy^2z+35x^2y^2z

Rewrite as

                                               =3\cdot \:5y^2x^2zy+5\cdot \:5y^2x^2zx+7\cdot \:5y^2x^2z

Factor out common term 5y²x²z

                                                =5y^2x^2z\left(3y+5x+7\right)

Therefore,

15x^2y^3z+25x^3y^2z+35x^2y^2z=5y^2x^2z\left(3y+5x+7\right)

8 0
3 years ago
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