Isolate the m, go backwards for PEMDAS.
C = 2m + d
C (-d) = 2m + d (-d)
C - d = 2m
(C - d)/2 = 2m/2
m = (C - d)/2
m = (C - d)/2 is your answer
hope this helps
y = mx + b
5 = 12(-3) + b
5 = -36 + b
b = 41
y = -3x + 41
Answer:
The top angle of the triangle is, X = 68°.
Step-by-step explanation:
Let there is a triangle named PQR with bottom corner angles ∠ P and ∠ Q and the ∠ R is the angle at the top.
Now, given that ∠ P = 31° and ∠ Q = 81° and we have to find out ∠ R i.e. X.
In Δ PQR, we know, ∠ P + ∠ Q + ∠ R = 180°
⇒ 31° + 81° + X = 180°
⇒ X = 68°
Therefore, the top angle of the triangle is 68°. (Answer)
Answer:
I think standard form would be best because it is simplest.
Step-by-step explanation:
hope this helps
B
Hope this helps :)
Can I have Brainliest please
