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Alchen [17]
3 years ago
7

17n – 5n2 + 2n3; n = -1 I need help plz

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
3 0

Answer:

-24

Step-by-step explanation:

aalyn [17]3 years ago
3 0
<h2>Answer:</h2>

Look just replace the n's with -1.

<h2>Step-by-step explanation:</h2>

So, it will look something that's close to this.

17n – 5n2 + 2n3; n = -1

17(-1) – 5(-1)2 + 2(-1)3

Then evaluate.

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Find m2 ROL if<br><br> m2 ROC = 31° and<br><br> m2 COL = 52°<br><br> 0<br><br> L
Tamiku [17]

Answer:

<h3>83°</h3>

Step-by-step explanation:

Given the parameters

m2 ROC = 31° and

m2 COL = 52°

According to the diagram in the attachment;

m2 ROL =  m2 ROC + m2 COL

Substitute the given values into the expression as shown;

m2 ROL= 31°+52°

m2 ROL = 83°

8 0
3 years ago
Help !!! Thank you guys !
makkiz [27]

Answer:

d

Step-by-step explanation:

7 0
3 years ago
Solve for
faust18 [17]

Given equation : n(17+x)=34x−r.

We need to solve it for x.

Distributing n over (17+x) on left side, we get

17n + nx  = 34x - r.

Adding r on both sides, we get

17n+r + nx  = 34x - r+r.

17n + r + nx = 34x.

Subtracting nx from both sides, we get

17n + r + nx-nx = 34x-nx

17n + r = 34x -nx.

Factoring out gcf x on right side, we get

17x + r = x(34-n).

Dividing both sides by (34-n), we get

\frac{(17x + r)}{(34-n)} = \frac{x(34-n)}{(34-n)}

\frac{(17x + r)}{(34-n)} = x

<h3>Therefore, final answer is x=\frac{(17x + r)}{(34-n)}.</h3>
7 0
3 years ago
Read 2 more answers
Find center,foci, and vertices of ellipse (x+3)^2/21+(y-5)^2/25=1
sasho [114]
I don't know if we can find the foci of this ellipse, but we can find the centre and the vertices. First of all, let us state the standard equation of an ellipse. 

(If there is a way to solve for the foci of this ellipse, please let me know! I am learning this stuff currently.) 

\frac{(x-x_{1})^2}{a^2}+ \frac{(y-y_{1})^2}{b^2}=1

Where (x_{1},y_{1}) is the centre of the ellipse. Just by looking at your equation right away, we can tell that the centre of the ellipse is: 

(-3,5)

Now to find the vertices, we must first remember that the vertices of an ellipse are on the major axis. 

The major axis in this case is that of the y-axis. In other words, 

b^2>a^2 

So we know that b=5 from your equation given. The vertices are 5 away from the centre, so we find that the vertices of your ellipse are: 

(-3,10)
 & (-3,0)

I really hope this helped you! (Partially because I spent a lot of time on this lol) 

Sincerely,

~Cam943, Junior Moderator
6 0
3 years ago
A circle is cut from a square piece of cloth, as shown.
ziro4ka [17]

Answer:

area of a circle= πr²

= 3.14×18×18×

=1017.36 in²

8 0
3 years ago
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