Answer: The loser's card shows 6.
Explanation: Let's start by naming the first student A and the second student B.
Since the product of A and B are either 12, 15, or 18, let's list every single possibility, the first number being A's number and the second number being B's number.
1 12
1 15
1 18
2 6
2 9
3 4
3 5
3 6
4 3
5 3
6 2
6 3
9 2
12 1
15 1
18 1
Now, the information says that A doesn't know what B has, so we can immediately cross off all of the combinations that have the integer appearing once and once ONLY off, because if it happened once only, A would know of it straight away. Now, our sample space becomes much smaller.
1 12
1 15
1 18
2 6
2 9
3 4
3 5
3 6
6 2
6 3
Using this same logic, we know that we can cross off all of the digits that occur only once in B's column.
2 6
3 6
Now, A definitely knows what number B has because there is only one number left in B. Hence, we can conclude that the loser, B, has the integer 6.
Oh i done this yes sir u r correct
Answer:
19
----- = x
40-3a
Step-by-step explanation:
3(ax + 9) = -4 (-2 - 10x)
Distribute
3ax +27 = 8+40x
Subtract 3ax from each side
3ax-3ax +27 = 8+40x-3ax
27 = = 8+40x-3ax
Subtract 8 from each side
27-8 = 8-8+40x-3ax
19 = 40x-3ax
Factor an x on the right side
19 = x(40-3a)
Divide each side by 40-3a
19/(40-3a) = x(40-3a)/(40-3a)
19
----- = x
40-3a
Answer:
Sid : [tied up] This is either really good or really bad.
Answer:
It is 1) True hope this helps
