We are asked for the number of <span>six-digit odd numbers that can be formed. the left-most digit should not be zero because it make the number -five digit already. An odd number ends only in 1, 3, 5, 7 and 9. Using counting, the 6th digit can only have 5 numbers, the 5th, 4th, 3rd, and 2nd can have, 10 numbers. The first number can only have 9 numbers. Hence the total number is 450,000</span>
Answer: (7, 20)
Concept:
There are three general ways to solve systems of equations:
- Elimination
- Substitution
- Graphing
Since the question has specific requirements, we are going to use <u>substitution </u>to solve the equations.
Solve:
<u>Given equations</u>
y = 3x - 1
2x + 6 = y
<u>Substitute the y value since both equations has isolated [y]</u>
2x + 6 = 3x - 1
<u>Add 1 on both sides</u>
2x + 6 + 1 = 3x - 1 + 1
2x + 7 = 3x
<u>Subtract 2x on both sides</u>
2x + 7 - 2x = 3x - 2x

<u>Find the value of y</u>
y = 3x - 1
y = 3(7) - 1
y = 21 - 1

Hope this helps!! :)
Please let me know if you have any questions
Use quotient rule to find y"
y" = [-(x-3)-(1-x)]/(x-3)^2 = 2/(x-3)^2
y" = -4/(x-3)^3
-4/(x-3)^3 > 0
(x-3)^3 < 0
x-3 < 0
x< 3
hope this help
If we factor -1/4 out of that expression it looks like this: -1/4(2x + 5)
In order to do this, we need to divide each term by that -1/4. Then use them in a parenthesis together.
(-1/2x)/(-1/4) = 2x
(-5/4)(-1/4) = 5
So we use them together at (2x + 5)