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blsea [12.9K]
3 years ago
5

Please help me find x. I really don't get it.

Mathematics
1 answer:
inysia [295]3 years ago
3 0

Answer:

  x = 11

Step-by-step explanation:

The relationship between the sine and cosine functions can be written as ...

  sin(x) = cos(90 -x)

  sin(A) = cos(90 -A) = cos(B) . . . . substituting the given values

Equating arguments of the cosine function, we have ...

 90 -(3x+4) = 8x -35

  86 -3x = 8x -35

  86 +35 = 8x +3x . . . . . add 3x+35 to both sides

  121 = 11x . . . . . . . . . . . . collect terms

  121/11 = x = 11 . . . . . . . . divide by 11

_____

<em>Comment on the solution</em>

There are other applicable relationships between sine and cosine as well. The result is that there are many solutions to this equation. One set is ...

  11 +(32 8/11)k . . . for any integer k

Another set is ...

  61.8 +72k . . . . . for any integer k

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Answer:

<h2>The answer is 72°</h2>

Step-by-step explanation:

Since < RQS = < QLK and < RQS = x

< QLK is also x

< QLK and < KLM lie on a straight line

Angles on a straight line add up to 180°

To find x add < QLK and < KLM and equate them to 180°

That's

< QLK + < KLM = 180°

x + x - 36 = 180

2x = 180 - 36

2x = 144

Divide both sides by 2

We have the final answer as

<h3>x = 72°</h3>

Hope this helps you

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Answer:

Step-by-step explanation:

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3 years ago
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8. While solving the equation log,(8x) – log,(x2 - 1) = log, 3, Karla found possible solutions at x=3
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The possible solution to the equation given is 3 and -1/3

<h3>Laws of logarithm</h3>

Given the logarithmic expression given as:

log,(8x) – log,(x^2 - 1) = log, 3

Applying the product and quotient rule will give:

log(8x/x^2-1) = log3

8x/x^2-1 = 3

Cross multiply

8x = 3x^2 - 3

3x^2 - 8x - 3 = 0

3x^2 -9x + x - 3 = 0

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x - 3 = 0 and 3x = -1

x = 3 and -1/3

Hence the possible solution to the equation given is 3 and -1/3

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