Answer:
djdjdjeueueuududhfh ch by by CV
Answer:
Step-by-step explanation:
Prime factorization requires dividing by primes starting with smallest prime number
402/2=201
201/3=67, 67 is prime so we cannot go further so the prime factorization of 402 is
2X3X67
For simple integer factors as this one has, you want to find two values for the quadratic in the form ax^2+bx+c. Let the two values be j and k. These two values must satisfy two conditions.
jk=ac=10 and j+k=b=11, so j and k must be 1 and 10.
Now replace bx with jx and kx...
2x^2+x+10x+5 now factor 1st and 2nd pair of terms.
x(2x+1)+5(2x+1)
(x+5)(2x+1)
Answer:
pt 1 is 3/5
Step-by-step explanation:
cuz i know
