At x = -4 and -8
Take the derivative of the given equation to find rate of change of the graph.
f'(x) = 6x^2 + 72x + 192
At a horizontal tangent, f'(x) = 0, so set the equation equal to 0 and solve. Eventually you get x = -4 and -8
Answer:
b= -4
Step-by-step explanation:
On both sides of the equation has distributive property. We need to solve that first. Let's start with the left side of the equation.
*Positive multiplied by a negative equals a negative
-2b+2(b-10)= 2(10+5b)
-2b+2b-20= 2(10+5b)
-20= 2(10+5b)
Now let's solve the right side of the equation
-20= 20+10b
-20 -20
-40 = 10b
-40/10 = 10b/10
b= -4
Hope this helps!
The two tangent lines for each circle are the same length. Set the equations to equal and solve for x.
1. 4x + 3 = 3x +12
Subtract 3x from each side:
x +3 = 12
Subtract 3 from both sides:
x = 9
2. -2 + x = 2x -7
Subtract 2x from both sides:
-2 - x = -7
Add 2 to each side:
-x = -5
Multiply both sides by -1:
x = 5
Hey there!
3^2 + 7 • 2
3^2 = 3 • 3 = 9
9 + 7 • 2
7 • 2 = 14
9 + 14 = 23
Answer: 23 ☑️
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
Answer:
y = 2x + 0
Step-by-step explanation:
the formula is y = mx + b
m = slope = change in y/change in x = (84 - 76)/(42 - 38) = 2
Slope is 2.
b is the y-intercept, which is the coordinate when x = 0. To find b, substitute any coordinate from the table. Let's use (38, 76)
y = 2x + b
76 = 2(38) + b
76 = 76 + b
b = 0
So the equation is y = 2x + 0
