Answer:
i₃ > i₁ > i₂
Explanation:
For this exercise we use the resistance ratio
R = ρ
where ρ is the resistivity of the wire, in this case it is the same for all three cases, l the length and A the area of the wire.
We have three cases
a) length l = L
area A = A
b) length l = 2L
area A = A
c) length l = L
area A = 2A
we calculate the resistance for each case
a) R₁ = ρ L / A
b) R₂ = ρ 2L / A
R₂ = 2 ρ L / A
R₂ = 2 R₁
c) R₃ = ρ L / 2A
R₃ = ½ ρ L / A
R₃ = 0.5 R₁
therefore when the connect of the circuit is carried out we can use ohm's law
V = i R
i = V / R
whereby
a) i₁ = V / R₁
b) i₂ = V / 2R₁
i₂ = ½ i₁
i₂ = 0.5 i₁
c) i₃ = V / 0.5 R₁
i₃ = 2 I₁
the order from highest to lowest in the current is
i₃ > i₁ > i₂
The answer for you question would be : Soprano
One of the type of voice that could produce a pitch that has a speed of 343 m/s and a wavelength of 0.68 m would be soprano
hope this helps
Answer:
E = 2k
Explanation:
Gauss's law states that the electric flux equals the wax charge between the dielectric permeability.
We must define a Gaussian surface that takes advantage of the symmetry of the problem, let's use a cylinder with the faces perpendicular to the line of charge. Therefore the angle between the cylinder side area has the same direction of the electric field which is radial.
Ф = ∫ E . dA = E ∫ dA = q_{int} /ε₀
tells us that the linear charge density is
λ = q_ {int} /l
q_ {int} = l λ
we substitute
E A = l λ /ε₀
is area of cylinder is
A = 2π r l
we substitute
E =
E =
the amount
k = 1 / 4πε₀
E = 2k
Answer:
88 m/s
Explanation:
To solve the problem, we can use the following SUVAT equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
d is the distance covered
For the car in this problem, we have
d = 484 m is the stopping distance
v = 0 is the final velocity
is the acceleration
Solving for u, we find the initial velocity: