A gust of wind pushes a beach ball with a force of 9 newtons. the ball rolls 10 meters in 3 seconds. what is the power of the wi
nd?
2 answers:
You might be interested in
Answer:
Part a)
tex]V = -1 \times 10^8 Volts[/tex]
Part b)
Part c)
Explanation:
Part a)
Net charge distribution on each shell is given as
On surface of radius "a"
on radius "b"
on radius "c"
Now potential at the outer shell is
Part b)
Since copper sphere is a conducting sphere so here it will be an equi potential surface
So the potential will remain same throughout the surface of this sphere
Now we can say
Part c)
Now electric potential at inner sphere is given as
Answer:
a) V = -0.227 mV
b) V = -0.5169 mV
Explanation:
a)
Inside a sphere with a uniformly distributed charge density, electric field is radial and has a magnitude
E = (qr) / (4πε₀R³)
As we know that
V = -
By solving above equation, we get
V = (-qr²) / (8πε₀R³)
When
R = 1.81 cm
r = 1.2 cm
q = +2.80 fC
ε₀ = 8.85 × 10⁻¹²
V = (-2.80 × 10⁻¹⁵ × (1.2 × 10⁻²)²) / (8 × 3.14 × 8.85 × 10⁻¹² × (1.81 × 10⁻²)³)
V = -2.27 × 10⁻⁴ V
V = -0.227 mV
b)
When
r = R
R = 1.81 cm
q = +2.80 fC
ε₀ = 8.85 × 10⁻¹²
V = (-qR²) / (8πε₀R³)
V = (-q) / (8πε₀R)
V = (-2.80 × 10⁻¹⁵) / (8 × 3.14 × 8.85 × 10⁻¹² × (1.81 × 10⁻²))
V = -5.169 × 10⁻⁴ V
V = -0.5169 mV