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2 years ago

Simplify these equations 8y+2+3y-5

Mathematics

1 answer:

Alex777 [14]2 years ago

5 0

The answe to this equation is 11y-3

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In the triangle below, ∠Q is a right angle. Which ratio would be equivalent to the ratio of sin∠R?

MrMuchimi

Answer:

b) cos∠S

Step-by-step explanation:

sin ∠R = SQ/SR

cos S

Correct option is b)

4 0

3 years ago

ETF is an example of

Elena-2011 [213]

I believe the answer would be B. money market funds.

7 0

3 years ago

BRAINLIEST ASAP! PLEASE HELP ME :)

Afina-wow [57]

Answer:

$\large \boxed{\textbf{30.54 yr}}$

Step-by-step explanation:

For species A,

$P =2000e^{0.05t}$

For species B,

$P =5000e^{0.02t}$

When their populations are equal,

$\begin{array}{rcl}2000e^{0.05t} & = & 5000e^{0.02t}\\e^{0.05t} & = & 2.5e^{0.02t}\\0.05t & = & \ln2.5 + 0.02t\\0.05t & = & 0.9163 + 0.02t\\0.03t & = & 0.9163\\t& = & \dfrac{0.9163}{0.03}\\\\& = & \mathbf{30.54}\\\end{array}\\\text{The populations of species A and B will be the same in $\large \boxed{\textbf{30.54 yr}}$}$

The diagram below shows the population of Species A overtaking that of Species B in about 30.5 yr.

3 0

3 years ago

The sum of two numbers is 8. Is it possible for the difference of the two numbers to also be 8? Why or why not

r-ruslan [8.4K]

Answer: yes

Step-by-step explanation: because you would get the same number cause anything plus or even divided by 0 then 8 each time you try ex: 8 + 0 = 8

8 - 0 = 8

brainliest plz

4 0

2 years ago

Two children own two-way radios that have a maximum range of 3 miles. One leaves a certain point at 1:00 P.M., walking due north

Grace [21]

Answer:

The answer is 21 minutes

Step-by-step explanation:

We use the equation Xf = Xo + vt

1) At 1:00 PM, child one leaves the starting point heading north at a constant velocity of 6 mi/hr or .1 [mi/min] (divide by 60 to convert from [mi/hr] to [mi/min])

2) He walks for 15 minutes before kid 2 starts walking. In 15 minutes he is able to cover 1.5 [mi]

$x_{1f1} =x_{o} +v_{1} t_{1} \\x_{1f1} =0+.1(15)\\x_{1f1} =1.5 [mi]$

3) Now, child 2 starts walking and we know that when the range reaches 3 miles, they won´t be able to communicate. So the sum of the final position of child 1 and child 2 must be 3[mi]

Child 1 final position => $x_{1f} = x_{1f1} +v_{1} t\\x_{1f} =1.5+v_{1} t$
Child 2 final position => $x_{2f} =0+v_{2} t$

4) Sum the equations and equate to 3

$x_{1f} +x_{2f} =3$

5) Substitute the values we already know

$1.5+v_{1} t+v_{2}t=3\\ 1.5+.1t+.15t=3\\1.5+.25t=3\\t=\frac{3-1.5}{.25} \\t=6 [min]$

6) in 15 + 6 minutes they will be 3miles apart

7) In 21 minutes they will still be able to communicate with one another.

7 0

3 years ago