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ella [17]
3 years ago
13

Solve -9 2/7-(-10 3/7)

Mathematics
2 answers:
Illusion [34]3 years ago
7 0

Answer:

1.14285714286

Step-by-step explanation:

swat323 years ago
4 0

Answer:

1 1/7

Step-by-step explanation:

Hope this helps

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Plz help its a benchmark
Darya [45]

Answer:

2 is the answer

Step-by-step explanation:

35+14=49

49/7=7

7=(5+x)

x=2

7 0
3 years ago
Read 2 more answers
Slope of 1/2 and y-intercept is -5. ​
bija089 [108]

Answer:

Y= 1/2x-5

Step-by-step explanation:

4 0
3 years ago
Hantet used the work below to determine the percent equivalent to 1/8​
luda_lava [24]

Answer:

In step 4, she forgot to move the decimal.

Step-by-step explanation:

Everything else is correct, but Hantet forget to move the decimal places 2 points to the right to make it 8% instead of 0.08%.

Always remember that percent is OUT of 100.

Hope this helps :)

Nathan

7 0
3 years ago
Which transformation shows a translation of 3 units to the right?
Marina CMI [18]

It is the transformation shown in (B)

(look at one point of the letter P and how it moves precisely 3 units. Also there is only the move, no flipping of the figure)

4 0
4 years ago
Read 2 more answers
Find the midpoint of the line segment joining the points ​(10​,7​) and ​(negative 2​,negative 7​).
Basile [38]

The midpoint of the line segment joining the points ​(10​,7​) and ​(negative 2​,negative 7​) is (4, 0)

<h3><u>Solution:</u></h3>

Given that line segment joining the points ​(10​,7​) and ​(negative 2​, negative 7​)

Thus the two points are ​(10​, 7​) and (-2, -7)

The midpoint of two points (x_1, y_1) and (x_2, y_2) is given as:

M(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

\text {Here } x_{1}=10 \text { and } y_{1}=7 \text { and } x_{2}=-2 \text { and } y_{2}=-7

Substituting the values in formula, we get

\begin{array}{l}{M(x, y)=\left(\frac{10+(-2)}{2}, \frac{7+(-7)}{2}\right)} \\\\ {M(x, y)=\left(\frac{10-2}{2}, \frac{7-7}{2}\right)} \\\\ {M(x, y)=(4,0)}\end{array}

Thus the midpoint of line segment is (4, 0)

8 0
4 years ago
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