To get the greatest possible quotient, you need the biggest possible
dividend and the smallest possible divisor.
96,432 divided by 225 = 428.5666... <== greatest possible
23,469 divided by 522 = 44.9597... <== smallest possible
Answer: -44
Step-by-step explanation: PEMDAS(Parenthesis; Exponent; Multiply; Divide; Add; Subtract)
First you multiply the seven with the other seven to get 49. The problem will look like this: (-3) + 8 - 49. Now just add the -3 and 8. You'd get 5.
Now the problem looks like this: 5 - 49. And you then get -44.
Answer:
Proportion states that the two fractions or ratios are equal
Given the equation: 
By cross multiply we get;
Using distributive property; 
Subtract 0.4 from both sides we get;
Subtract 1.5x from both sides we get;
Divide both sides by 0.1 we get;
Simplify:
x = 56
Therefore, the value of x that satisfy the equation is, 56
Answer:
- number of multiplies is n!
- n=10, 3.6 ms
- n=15, 21.8 min
- n=20, 77.09 yr
- n=25, 4.9×10^8 yr
Step-by-step explanation:
Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...
mpy[n] = n·mp[n-1]
mpy[2] = 2
So, ...
mpy[n] = n! . . . n ≥ 2
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If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...
10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10
Then the larger matrices take ...
n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min
n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years
n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years
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For the shorter time periods (less than 100 years), we use 365.25 days per year.
For the longer time periods (more than 400 years), we use 365.2425 days per year.
