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3 years ago

13

The chef of a pizza place used 1/3 of a package of pepperoni and 1/6 of a package of

1 answer:

murzikaleks [220]3 years ago

4 0

Answer:

If the packages are the same size and everything and has the same volume, then it would be 1/6 more of a package.

Step-by-step explanation:

1/6

1/6

1/6

1/3 is equal to 2/6 because you can multiply the numerator (the top) and the denominator (the bottom number in a fraction) by 2 to get 2/6. The pepperoni usage of the package was 2/6, while the sausage was 1/6.

2/6 minus (-) 1/6 is equal to 1/6.

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Let a and b be roots of x² - 4x + 2 = 0. find the value of a/b² +b/a²

erastovalidia [21]

Answer:

$\dfrac{a}{b^2}+\dfrac{b}{a^2}=10$

Step-by-step explanation:

Given equation: $x^2-4x+2=0$

The roots of the given quadratic equation are the values of x when $y=0$ .

To find the roots, use the quadratic formula:

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=1, \quad b=-4, \quad c=2$

$\begin{aligned}\implies x & =\dfrac{-(-4) \pm \sqrt{(-4)^2-4(1)(2)}}{2(1)}\\& =\dfrac{4 \pm \sqrt{8}}{2}\\& =\dfrac{4 \pm 2\sqrt{2}}{2}\\& =2 \pm \sqrt{2}\end{aligned}$

$\textsf{Let }a=2+\sqrt{2}$

$\textsf{Let }b=2-\sqrt{2}$

Therefore:

$\begin{aligned}\implies \dfrac{a}{b^2}+\dfrac{b}{a^2} & = \dfrac{2+\sqrt{2}}{(2-\sqrt{2})^2}+\dfrac{2-\sqrt{2}}{(2+\sqrt{2})^2}\\\\& = \dfrac{2+\sqrt{2}}{6-4\sqrt{2}}+\dfrac{2-\sqrt{2}}{6+4\sqrt{2}}\\\\& = \dfrac{(2+\sqrt{2})(6+4\sqrt{2})+(2-\sqrt{2})(6-4\sqrt{2})}{(6-4\sqrt{2})(6+4\sqrt{2})}\\\\& = \dfrac{12+8\sqrt{2}+6\sqrt{2}+8+12-8\sqrt{2}-6\sqrt{2}+8}{36+24\sqrt{2}-24\sqrt{2}-32}\\\\& = \dfrac{40}{4}\\\\& = 10\end{aligned}$

6 0

2 years ago

Read 2 more answers

When you have > or <, the solutions are only in the shaded area.<br> True <br> or<br> False

alexira [117]

Answer: True

Step-by-step explanation: Because the solutions can not land on the dotted lines.

4 0

2 years ago

Read 2 more answers

It cost 5 dollars for a child ticket and 8 dollars for a adult ticket. Total tickets sold were 110 bringing in 820 dollars? How

omeli [17]

Number of child tickets bought is 20

<h3><u>Solution:</u></h3>

Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket

cost of each child ticket = 5 dollars

cost of each adult ticket = 8 dollars

Let "c" be the number of child tickets bought

Let "a" be the number of adult tickets bought

Total tickets sold were 110 bringing in 820 dollars

<em>Number of child tickets bought + number of adult tickets bought = 110</em>

c + a = 110 ----- eqn 1

<em><u>Also we can frame a equation as:</u></em>

Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

$c \times 5 + a \times 8 = 820$

5c + 8a = 820 -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "c" and "a"

From eqn 1,

a = 110 - c ------ eqn 3

Substitute eqn 3 in eqn 2

5c + 8(110 - c) = 820

5c + 880 - 8c = 820

-3c = - 60

c = 20

Therefore from eqn 3,

a = 110 - 20 = 90

a = 90

Therefore number of child tickets bought is 20

8 0

3 years ago

PLEASE HELP WILL MARK BRAINLIEST

Harlamova29_29 [7]

WHERES THE QUESTION IT WONT SHOW UP ON MY SCREEN POST IT AGAIN

3 0

3 years ago

In a survey of 3400 people asked about their ice cream preference, 1600 enjoyed chocolate, 1250 enjoyedvanilla, 1700 enjoyed min

velikii [3]

Answer:

Step-by-step explanation:

To understand the situations we must do a Venn diagram:

The total of people asked is 3400. Then,

a) For People who enjoyed vanilla but not chocolate or mint, seeing the diagram of Venn, we can deduce the equations:

$undefined$

b) For people who did not enjoy chocolate, vanilla or mint:

$undefined$

4 0

1 year ago