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3 years ago

Please can someone do itpleaseeeeeeee

Mathematics

1 answer:

alukav5142 [94]3 years ago

3 0

Answer:

a=250

b=10

done...

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Foster is centering a photo that is 1/1 2 inches wide on a scrapbook page that is 10 inches wide. How far from each side of the

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The answer would be 4 1/4 (4.25)
10-1.5=8.5/2=4.25

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3 years ago

Please help!! <br> Will mark and star!!

Kamila [148]

The answer is B. please mark me as brainlyest.

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3 years ago

Two sides of a parallelogram are 93 feet and 80 feet. The measure of the angle between these sides is 18°. Find the area of the

azamat

<h3>Answer: 2299 square feet</h3>

Work Shown:

area = a*b*sin(C)

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2 years ago

Which statement or statements are TRUE?

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3 years ago

Read 2 more answers

Which statement describes if there is an extraneous solution to the equation √x-3 = x-5? A. there are no solutions to the equati

Brrunno [24]

Remember that <span>an extraneous solution of an equation, is the solution that emerges from solving the equation but is not a valid solution.

Lets solve our equation to find out what is the extraneous solution:
</span> $\sqrt{x-3} =x-5$
$(\sqrt{x-3})^2 =(x-5)^2$
$x-3=x^2-10x+25$
$x^2-11x+28=0$
$(x-4)(x-7)=0$
$x-4=0$ and $x-7=0$
$x=4$ and $x=7$
<span>
So, the solutions of our equation are </span> $x=4$ and $x=7$ . Lets replace each solution in our original equation to check if they are valid solutions:
- For $x=7$
$\sqrt{x-3} =x-5$
$\sqrt{7-3} =7-5$
$\sqrt{4} =2$
$2=2$
We can conclude that 7 is a valid solution of the equation.

- For $x=4$
$\sqrt{x-3} =x-5$
$\sqrt{4-3} =4-5$
$\sqrt{1} =1$
$1 \neq 1$
We can conclude that 4 is not a valid solution of the equation; therefore, 4 is a extraneous solution.

We can conclude that the correct answer is: <span>D. the extraneous solution is x = 4</span>

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3 years ago