Evaluate 3x for x = −2, x = 1, and x = 3. Question 18 options: A) 1∕3, 0, 9 B) 1∕9, 3, 27 C) 9, 3, 27 D) 1∕9, 9, 27
icang [17]
Answer: B) 1/9, 3, 27
Step-by-step explanation:
Here, we need to evaluate
for ![x = -2, x = 1, \text{ and } x = 3.](https://tex.z-dn.net/?f=x%20%3D%20-2%2C%20x%20%3D%201%2C%20%5Ctext%7B%20and%20%7D%20x%20%3D%203.)
So, we substitute values of x in the given function.
At x= -2, we have
![3^{-2}=\dfrac{1}{3^2}=\dfrac{1}{9}\ \ \ [\because\ a^{-n}=\dfrac{1}{a^n}]](https://tex.z-dn.net/?f=3%5E%7B-2%7D%3D%5Cdfrac%7B1%7D%7B3%5E2%7D%3D%5Cdfrac%7B1%7D%7B9%7D%5C%20%5C%20%5C%20%5B%5Cbecause%5C%20a%5E%7B-n%7D%3D%5Cdfrac%7B1%7D%7Ba%5En%7D%5D)
At x= 1, we have
![3^1=3](https://tex.z-dn.net/?f=3%5E1%3D3)
At x= 3
![3^3=3\times3\times3=27](https://tex.z-dn.net/?f=3%5E3%3D3%5Ctimes3%5Ctimes3%3D27)
So, the values of
for
Thus, the correct answer is B) 1/9, 3, 27
Slope = 0
b = 5
equation
y = 5