Answer:
The statement is correct since 500 gallon of gasolin produces 4.56 ton of carbon dioxide.
Explanation:
The combustion of gasoline follows the reation bellow:
C₈H₁₈ (l) + 17,5O₂ (g) → 8CO₂ (g) + 9H₂O (g)
This means that each mol of octane produces 8 mol of CO₂.
1 gallon ______ 4546.09 mL C₈H₁₈
500 gallon ____ x
x = 2,273,045.00 mL C₈H₁₈
1 mL gasoline ______________ 0.703 g
2,273,045.00 mL C₈H₁₈ ____ y
y = 1,597,950.635 g C₈H₁₈
1 mol C₈H₁₈ _____ 126.239 g
y _____ 1,597,950.635 g
y = 12,966.274 mol C₈H₁₈
1 mol C₈H₁₈ ___________ 8 mol CO₂
12,966.274 mol C₈H₁₈ ____ w
w = 103,730.192 mol CO₂
1 mol CO₂ ______________ 44 g
103,730.192 mol CO₂______ z
z = 4564128.448 g CO₂
500 gallon of gasolin produces 4.56 ton of carbon dioxide.
