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Afina-wow [57]
3 years ago
13

A website promoting the use of alternative energy vehicles and hybrid technologies claims that "A typical automobile in the USA

uses about 500 gal of gasoline every year, producing about 5 tons of carbon dioxide." To determine the truth of this statement, calculate how many tons of carbon dioxide are produced when 500.0 gallon of gasoline are combusted. Assume that the primary ingredient in gasoline is octane, C₈H₁₈(l), which has a density of 0.703?
Chemistry
1 answer:
svetlana [45]3 years ago
4 0

Answer:

The statement is correct since 500 gallon of gasolin produces 4.56 ton of carbon dioxide.

Explanation:

The combustion of gasoline follows the reation bellow:

C₈H₁₈ (l) + 17,5O₂ (g) → 8CO₂ (g) + 9H₂O (g)

This means that each mol of octane produces 8 mol of CO₂.

1 gallon ______ 4546.09 mL C₈H₁₈

500 gallon ____    x

x = 2,273,045.00 mL C₈H₁₈

1 mL gasoline ______________ 0.703 g

2,273,045.00 mL C₈H₁₈ ____  y

y = 1,597,950.635 g C₈H₁₈

1 mol C₈H₁₈ _____ 126.239 g

            y          _____  1,597,950.635 g

y = 12,966.274 mol C₈H₁₈

1 mol C₈H₁₈ ___________ 8 mol CO₂

12,966.274 mol C₈H₁₈ ____  w

w = 103,730.192 mol CO₂

1 mol CO₂ ______________ 44 g

103,730.192 mol CO₂______   z

z = 4564128.448 g CO₂

500 gallon of gasolin produces 4.56 ton of carbon dioxide.

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What is the mass of carbon monoxide (CO) gas if the gas occupies a volume of 4.1 L at 2.0 atm of pressure and -73oC?
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1. element with three occupied energy levels and<br> one valence electron
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The pH of a neutral solution is below 7 above 7 7 7.5
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The pH scale ranges from 0 to 14 and goes from acidic to alkaline, where 7 - the center of the scale - is the most neutral.

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4 0
3 years ago
A 1.0 mole sample of fluorine gas at 25 °C has an average molecular velocity of 415 m/s. What is the total KE of the gas sample?
Mariana [72]

The total kinetic energy of the gas sample is 3.3 KJ

<h3>What is kinetic energy? </h3>

This is the energy possessed by an object in motion. Mathematically, it can be expressed as:

KE = ½mv²

Where

  • KE is the kinetic energy
  • m is the mass
  • v is the velocity

<h3>How to determine the mass of the fluorine gas</h3>
  • Molar mass of fluorine gas = 38 g/mol
  • Mole of fluorine gas = 1 mole
  • Mass of fluorine gas = ?

Mass = mole × molar mass

Mass of fluorine gas = 1 × 38

Mass of fluorine gas = 38 g

<h3>How to determine the KE of the gas sample</h3>
  • Mass (m) = 38 g = 38 / 1000 = 0.038 Kg
  • Velocity (v) = 415 m/s
  • Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 0.038 × 415²

KE = 3272.275 J

Divide by 1000 to express in kilojoule

KE = 3272.275 / 1000

KE = 3.3 KJ

Learn more about energy:

brainly.com/question/10703928

#SPJ1

4 0
2 years ago
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