Im pretty sure its hypothesis
Answer:
Individual Characteristics are properties of physical evidence that can be attributed to a common source with a high degree of certainty. Examples of individual evidence include anything that contains nuclear DNA, toolmarks, and fingerprints.
Explanation:
A wavy-haired parent can either contribute a C or an s, so two wavy-haired parents have a fifty percent chance of having a wavy-haired child, a twenty-five percent chance of having a curly-haired child, and a twenty-five percent chance of having a straight-haired child.
Admitting that the "a" is a capital A for normal pigmentation and "d" is a capital D for dimpled chin, meaning that these are the dominant traits, the fraction expected to be albino with a non-dimpled chin is of 1/16.
When two heterozygous are crossed and two characteristics are being analysed, the offspring quantity that will possess the two recessive traits can be represented by 1/16. This is easily confirmed when a Punnett square is made. Considering that both parents were heterozygous, on both sides of the crossing in the Punnett square, you would have the following alleles' combination: AD, Ad, aD, and ad. The offspring that would be homozygous recessive (aadd) would correspond to only 1/16.
Answer:
A
Explanation:
cells divide by mitosis hope this helps
