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3 years ago

HELPPPPP Rename 1/4 and 1/8 using the least common denominator.

Mathematics

1 answer:

kaheart [24]3 years ago

3 0

Answer:

the LCD or least common denominator is 8

Step-by-step explanation:

2/8 and 1/8

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What is the exponential regression equation that fits these data? y x 1 4 2 8 3 27 4 85 5 250 6 600

Volgvan

Answer:

its is C because the other ones are obvious wrong. So it has to be C plus i did this test.

Step-by-step explanation:

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2 years ago

The point slope form of a line with a slope of 2 through (1, 4) is y – 4 = 2(x – 1).

ella [17]

Answer:

TRUE

Step-by-step explanation:

y-4 = 2(x-1)

here, 4 is representing the y value and 1 is representing the x value.

And the slope is 2.

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

callie spent 3/4 hour on a science report and 1/3 hour on a social studies report. What fraction of an hour longer did she spend

seraphim [82]

3/4+1/3=9/12+4/12=13/12 of an hour

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7 0

3 years ago

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0

3 years ago