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olga_2 [115]
4 years ago
9

2.06 ? 2.060А. <B.>C.=​

Mathematics
1 answer:
agasfer [191]4 years ago
8 0

2.06 is equivalent to 2.060

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ROUND TO THE NEAREST TENTH.
Ulleksa [173]

Answer:

I believe the answer is cutting through open fields

Step-by-step explanation:

If you needed to get somewhere but you didn't have a direct path to where you needed to go; as in needing to make turns, then you should be able to get there faster if you go at a diagonal angle to the point in which you are trying to reach.

3 0
3 years ago
Edwin writes an absolute value equation to determine the values that are 0.3 units from 3.9.
Fittoniya [83]

The absolute value equation written by Edwin according to his intention in the task content is; |x -3.9| = 0.3 and The values that are 0.3unuts from 3.9 are; 4.2 and 3.6.

<h3>What absolute value equation can be written by Edwin to find the numbers which are 0.3 units away from 3.9 on the number line?</h3>

Since the numbers in discuss are required to be 0.3 units from 3.9, it follows that one number is greater while the other is less than 3.9 and hence the required absolute value equation is;

|x -3.9| = 0.3. which can be solved as;

x-3.9 = 0.3; x =4.2.

Or

x -3.9 = -0.3; x = 3.6.

Read more on absolute value equation;

brainly.com/question/26954538

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4 0
2 years ago
I have 7 hundreds blocks, 5 tens blocks, and 8 ones blocks. I use my blocks to model two 3-digit numbers. What could my two numb
lawyer [7]
There 7 blocks of hundreds which means each such block is equivalent to 100.
There are 5 blocks of tens, which means each such block is equivalent to 10.
There are 8 blocks of ones, which means each such block is equivalent to 1.

The total of these blocks will be = 7(100) + 5(10) + 8(10) = 758

We can make several two 3-digit numbers from these blocks. An example is listed below:

Example:
Using 3 hundred block, 2 tens blocks and 4 ones block to make one number and remaining blocks to make the other number. The remaining blocks will be 4 hundred blocks, 3 tens blocks and 4 ones blocks
The two numbers we will make in this case are:

1st number = 3(100) + 2(10) + 4(1) = 324
2nd number = 4(100) + 3(10) + 4(1) = 434

The sum of these two numbers is  = 324 + 434 = 758
i.e. equal to the original sum of all blocks.

This way changing the number of blocks in each place value, different 3 digit numbers can be generated. 
5 0
3 years ago
A ladder 25 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2
Artemon [7]

Answer:

a) The height decreases at a rate of \frac{7}{12} ft/sec.

b) The area increases at a rate of \frac{527}{24} ft^2/sec

c) The angle is increasing at a rate of \frac{1}{12} rad/sec

Step-by-step explanation:

Attached you will find a sketch of the situation. The ladder forms a triangle of base b and height h with the house. The key to any type of problem is to identify the formula we want to differentiate, by having in mind the rules of differentiation.

a) Using pythagorean theorem, we have that 25^2 = h^2+b^2. From here, we have that

h^2 = 25^2-b^2

if we differentiate with respecto to t (t is time), by implicit differentiation we get

2h \frac{dh}{dt} = -2b\frac{db}{dt}

Then,

\frac{dh}{dt} = -\frac{b}{h}\frac{db}{dt}.

We are told that the base is increasing at a rate of 2 ft/s (that is the value of db/dt). Using the pythagorean theorem, when b = 7, then h = 24. So,

\frac{dh}{dt} = -\frac{2\cdot 7}{24}= \frac{-7}{12}

b) The area of the triangle is given by

A = \frac{1}{2}bh

By differentiating with respect to t, using the product formula we get

\frac{dA}{dt} = \frac{1}{2} (\frac{db}{dt}h+b\frac{dh}{dt})

when b=7,  we know that h=24 and dh/dt = -1/12. Then

\frac{dA}{dt} = \frac{1}{2}(2\cdot 24- 7\frac{7}{12}) = \frac{527}{24}

c) Based on the drawing, we have that

\sin(\theta)= \frac{b}{25}

If we differentiate with respect of t, and recalling that the derivative of sine is cosine, we get

\cos(\theta)\frac{d\theta}{dt}=\frac{1}{25}\frac{db}{dt} or, by replacing the value of db/dt

\frac{d\theta}{dt}=\frac{2}{25\cos(\theta)}

when b = 7, we have that h = 24, then \cos(\theta) = \frac{24}{25}, then

\frac{d\theta}{dt} = \frac{2}{25\frac{24}{25}} = \frac{2}{24} = \frac{1}{12}

7 0
3 years ago
1.
lord [1]

Okay I'm not sure which you need help with but.

First one, it means how did you feel about how the worksheets were set up

Then, about what you learned

How you felt about tests

And for the last one you could say thing like

How you felt about obstacles, the teachers/professors, pressure, how much you think you learned, how you feel at the end of the school year versus the beginning, or how you grew as a student/person. You can pick one or two or your own, those are just some ideas.

How is this your last day at school? You are quite lucky

6 0
3 years ago
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