For this case we have to;
We have that an equation in slope-intercept form is given by:

Where:
m is the slope
b is the cut point with the y axis
Also, by definition, two lines are perpendicular when the product of their slopes is -1. That is:
We have the line as data: 
Then 
We found
:





Thus, 
We must find
:
We know that
passes through the point
We substitute the point in the equation of
:

Thus, 
Then the equation in slope-intercept for the line that passes through (5,0) and is perpendicular to the line described by
is: 
Answer:

Answer:
4
Step-by-step explanation:
Slope= y2-y1/x2-x1
(1,5) is placed as (x1,y1) and (-1,-3) is placed as (x2,y2)
Plug it in
-3-5/-1-1
Simplify
-8/-2 = 4
Slope=4
Answer:
<h3>
Vertex Form</h3>
Step-by-step explanation:
Vertex form of quadratic function with vertex (h, k) is y=a(x-h)²+k,
So y= (x - 2)² - 9 is vertex form with vertex (2, -9)

Since, we know that in Elimination method we have to first the value of "x" or either "y". For that we have to multiply a number which makes the both equation's "x" or "y" equal so that we cut cancel it and find the solution.
Here's an example:
Like, in here
Equation 1: - 2x + 3y = 9
Equation 2: - 8x - 7y = 10
We can see that in "Equation 1" the first number is "- 2x" and in "Equation 2" the first number is "-8x". So, what we do in Elimination method is that we have to make the first number of both the equations equal or same.
Eg:
- 2x + 3y = 9.
- 8x + 7y = 10--(ii)
Now,we can see that in "Equation 2" the first number is "8x" whereas in "Equation 1" the first number is "-2x". We have to multiply with any number that makes the both the first number of equation is same.
So, I'm taking the number "4" to multiply it with equation 1, which gives us the result,

Now, we've subtract both the equation to get the results.

The answer Is: C because it’s a line that passss through the two points in the table