Sonya drops a marble while standing on a deck 7 7/8 feet above the ground. The marble falls 4 1/4 feta from Sonya's hand to the

Question

3 years ago

11

deck, and then rolls and falls to the ground. What is the total vertical distance that the marble falls?

2 answers:

Greeley [361] · Answer 1 · 2022-07-03T14:07:29+03:00

Answer:

$12\dfrac{1}{8}\ feet$

Step-by-step explanation:

Sonya drops a marble while standing on a deck $7 \dfrac{7}{8}$ feet above the ground.

The marble falls $4 \dfrac{1}{4}$ feet from Sonya's hand to the deck, and then rolls and falls to the ground.

So, the ball falls $4 \dfrac{1}{4}$ feet from Sonya's hand to the deck and $7 \dfrac{7}{8}$ from the deck to the ground, in total

$4\dfrac{1}{4}+7\dfrac{7}{8}=4\dfrac{2}{8}+7\dfrac{7}{8}=(4+7)+\dfrac{2+7}{8}=11+\dfrac{9}{8}=11+1\dfrac{1}{8}=12\dfrac{1}{8}\ feet$

Serga [27] · Answer 2 · 2022-07-03T15:50:06+03:00

Serga [27]3 years ago

3 0

Answer: just subtract 7 7/8 - 4 1/4 :)

Step-by-step explanation: