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marishachu [46]
3 years ago
11

Sonya drops a marble while standing on a deck 7 7/8 feet above the ground. The marble falls 4 1/4 feta from Sonya's hand to the

deck, and then rolls and falls to the ground. What is the total vertical distance that the marble falls?
Mathematics
2 answers:
Greeley [361]3 years ago
8 0

Answer:

12\dfrac{1}{8}\ feet

Step-by-step explanation:

Sonya drops a marble while standing on a deck 7 \dfrac{7}{8} feet above the ground.

The marble falls 4 \dfrac{1}{4} feet from Sonya's hand to the deck, and then rolls and falls to the ground.

So, the ball falls 4 \dfrac{1}{4} feet from Sonya's hand to the deck  and 7 \dfrac{7}{8} from the deck to the ground, in total

4\dfrac{1}{4}+7\dfrac{7}{8}=4\dfrac{2}{8}+7\dfrac{7}{8}=(4+7)+\dfrac{2+7}{8}=11+\dfrac{9}{8}=11+1\dfrac{1}{8}=12\dfrac{1}{8}\ feet

Serga [27]3 years ago
3 0

Answer: just subtract 7 7/8 - 4 1/4 :)

Step-by-step explanation:

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