If G is the midpoint of FH find FG
fg=11x-7 gh= 3x+9
The function f(x) is continous on the interval (-3, 4). If we know that f(-1) = 4 and f(3) = 7, what can we say about the output
1 answer:
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Answer:
Option B
Step-by-step explanation:
we have
we know that
<u>The vertical line test </u>is a visual way to determine if a curve is a function or not. A function can only have one value of y for each unique value of x
In this problem
The given function passes the vertical line test
therefore
f(x) is a function
<u>The Horizontal Line Test</u> is a test use to determine if a function is one-to-one
If a horizontal line intersects a function's graph more than once, then the function is not one-to-one.
In this problem
The given function fails the horizontal line test
because for f(x)=0 x=-3, x=-1, x=3
therefore
It is no a one-to-one function
Answer:
In a rhombus, the diagonals bisect at right angles. That means half the diagonals form a right angle triangle then we can try the Pythagorean theorem. so -
one side of triangle = 6/2 =3 (half of the diagonal)
other side = 8/2 = 4
a^2 + b^2 = c2
3 ^2 + 4^2 = c^2
9+16 = c^2
c^2=25
c = = 5
the hypothenus forms one side of the rhombus and here the hypothenus is 5, so the lenght of a side is 5 !
