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3 years ago

And the first derivative off(n) = 15e

Mathematics

2 answers:

icang [17]3 years ago

8 0

I had a question like this and it was 0

kirill [66]3 years ago

3 0

Answer:

the answer is 0.

Step-by-step explanation:

The answer is 0, I had a question like this before

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PLZ HELP PLZ PLZ HELP

Dmitrij [34]

2-1.75=.25

.25/2=.125/1

.125 is the answer

3 0

2 years ago

Simply by adding like terms: -7x^2*y*z + 3y*z^2 - z*x^2*y - 4y

Bumek [7]

9514 1404 393

Answer:

-8x^2·y·z +3y·z^2 -4y

Step-by-step explanation:

It can be helpful to make sure the variables in each term are in alphabetical order. This makes it easier to see "like" terms. The variables in each term are ...

x^2 y z

y z^2

x^2 y z

Only the first and third terms are like terms, so those are the only ones that can be combined. Their coefficients are -7 and -1, so sum to -8. The combined term is of highest degree, so in standard form we list that term first.

= -8x^2·y·z +3y·z^2 -4y

6 0

3 years ago

Select the ratio equivalent to tan (o)

CaHeK987 [17]

Answer:

tangent = opp over adj

Step-by-step explanation:

6 0

3 years ago

The resting heart rate for an adult horse should average about µ = 47 beats per minute with a (95% of data) range from 19 to 75

KatRina [158]

Answer:

a. 0.0582 = 5.82% probability that the heart rate is less than 25 beats per minute.

b. 0.1762 = 17.62% probability that the heart rate is greater than 60 beats per minute.

c. 0.7656 = 76.56% probability that the heart rate is between 25 and 60 beats per minute

Step-by-step explanation:

Empirical Rule:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean:

$\mu = 47$

(95% of data) range from 19 to 75 beats per minute.

This means that between 19 and 75, by the Empirical Rule, there are 4 standard deviations. So

$4\sigma = 75 - 19$

$4\sigma = 56$

$\sigma = \frac{56}{4} = 14$

a. What is the probability that the heart rate is less than 25 beats per minute?

This is the p-value of Z when X = 25. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{25 - 47}{14}$

$Z = -1.57$

$Z = -1.57$ has a p-value of 0.0582.

0.0582 = 5.82% probability that the heart rate is less than 25 beats per minute.

b. What is the probability that the heart rate is greater than 60 beats per minute?

This is 1 subtracted by the p-value of Z when X = 60. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 47}{14}$

$Z = 0.93$

$Z = 0.93$ has a p-value of 0.8238.

1 - 0.8238 = 0.1762

0.1762 = 17.62% probability that the heart rate is greater than 60 beats per minute.

c. What is the probability that the heart rate is between 25 and 60 beats per minute?

This is the p-value of Z when X = 60 subtracted by the p-value of Z when X = 25. From the previous two items, we have these two p-values. So

0.8238 - 0.0582 = 0.7656

0.7656 = 76.56% probability that the heart rate is between 25 and 60 beats per minute

3 0

3 years ago

The ideal gas law relates the pressure P , volume V , and temperature T of a fixed number of molecules of a gas in a container v

pochemuha

Answer:

K would be 375.

Step-by-step explanation:

You take the number you already have and divide it by the new number its giving. (0.06)

8 0

3 years ago

And the first derivative off(n) = 15e​

And the first derivative off(n) = 15e