And the first derivative off(n) = 15e

Mathematics

2 answers:

icang [17]2 years ago

8 0

I had a question like this and it was 0

kirill [66]2 years ago

3 0

Answer:

the answer is 0.

Step-by-step explanation:

The answer is 0, I had a question like this before

You might be interested in

What equation is graphed in this figure?

aniked [119]

Based on the graph, the slope is -3, and the y-intercept is 1. So your equation should be:

y = -3x + 1

The answer is C

y + 2 = -3(x - 1)

y + 2 = -3x + 3

y = -3x + 1

5 0

2 years ago

Read 2 more answers

W=pv for p, how do you get the answer?

xxMikexx [17]

Answer:

you need to have values for w and v

but u basically have to do

MOVE V TO THE OTHER SIDE

W/V=P

Step-by-step explanation:

HOPE I HELPED

PLS MARK BRAINLIEST

DESPERATELY TRYING TO LEVEL UP

✌ -ZYLYNN JADE ARDENNE

5 0

2 years ago

A bacteria culture initially contains 100 cells and grows at a rate proportional to its size. After an hour the population has i

bija089 [108]

Answer: $\bold{a)\ P(t)=P_o\cdot e^{t\cdot ln(2.7)}}$

b) 5314

c) ln 2.7

d) 4.6 hrs

<u>Step-by-step explanation:</u>

$P(t) = P_o\cdot e^{kt}\\\\\bullet \text{P(t) is the number of bacteria after t hours} \\\bullet P_o\text{ is the initial number of bacteria}\\\bullet \text{k is the rate of growth}\\\bullet \text{t is the time (in hours)}\\\\\\270=100\cdot e^{k(1)}\\2.7=e^k\\ln\ 2.7=\ln e^k\\\boxed{ln\ 2.7=k}\\\\\text{So the equation to find the number of bacteria is: }\boxed{P(t)=P_o\cdot e^{t\cdot ln(2.7)}}\\\\\\P(4)=100\cdot e^{4\cdot ln(2.7)}\\.\qquad =\boxed{5314}$

$10,000=100\cdot e^{t\cdot ln(2.7)}\\100=e^{t\cdot ln(2.7)}\\ln\ 100=ln\ e^{t\cdot ln(2.7)}\\ln\ 100=t\cdot ln(2.7)\\\dfrac{ln\ 100}{ln\ 2.7}=t\\\\\boxed{4.6=t}$