Answer:
The domain is all real numbers, and the range is all real numbers f(x) such that f(x) ≤ 4. You can check that the vertex is indeed at (1, 4). Since a quadratic function has two mirror image halves, the line of reflection has to be in the middle of two points with the same y value.
Answer:
x° is 66°
Step-by-step explanation:
From the given diagram, we have;
∠JIH = 105° Given
∠IDJ = 39° Given
Therefore, we have;
∠JID and ∠JIH are supplementary angles, by the sum of angles on a straight line
∴ ∠JID + ∠JIH = 180° by definition of supplementary angles
∠JID + 105° = 180° by substitution property
∠JID = 180° - 105° = 75° by angle subtraction postulate
∠JID = 75°
∠IDJ + ∠JID + ∠IJD = 180° by the sum of interior angles of a triangle
∠IJD = 180° - (∠IDJ + ∠JID) = 180° - (39° + 75°) = 66° angle subtraction postulate
∠IJD = 66°
∠x° ≅ ∠IJD, by vertically opposite angles
∴ ∠x° = ∠IJD = 66° by the definition of congruency
∠x° = 66°
Answer:
A rectangular garden has dimensions of 19 feet by 16 feet. A gravel path of equal width is to be built around the garden. How wide can the path be if there is enough gravel for 246 square feet?
OA 5ft
OB. 3 ft
OC. 41
OD. 5.5 ft
The answer is choice A.
We're told that the left and right walls of the cube (LMN and PQR) are parallel planes. Any line contained in one of those planes will not meet another line contained in another plane. With choice A, it's possible to have the front and back walls be non-parallel and still meet the initial conditions. If this is the case, then OS won't be paralle to NR. Similarly, LP won't be parallel to MQ.
I hope it's helpful for u but I am not sure my answer is right !
