Question

A ball is rolled at a velocity of 12m/sec.after 36 seconds,it comes to a stop what is the acceleration of the ball?

Answer 1

acceleration of ball is $\frac{-1}{3}\,\,m/sec^2$

Step-by-step explanation:

Initial Velocity = 12m/sec

time = 36 s

Final Velocity 0 m/sec (ball comes to stop)

Acceleration= ?

The formula used to find acceleration is:

$Acceleration=\frac{Final\,\,Velocity-Initial\,\,Velocity}{Time}$

Putting values and finding acceleration:

$Acceleration=\frac{Final\,\,Velocity-Initial\,\,Velocity}{Time}$

$Acceleration=\frac{0-12}{36}$

$Acceleration=\frac{-12}{36}$

$Acceleration=\frac{-1}{3}\,\,m/sec^2$

So, acceleration of ball is $\frac{-1}{3}\,\,m/sec^2$

Keywords: Acceleration

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