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3 years ago

A ball is rolled at a velocity of 12m/sec.after 36 seconds,it comes to a stop what is the acceleration of the ball?

Mathematics

1 answer:

miv72 [106K]3 years ago

8 0

acceleration of ball is $\frac{-1}{3}\,\,m/sec^2$

Step-by-step explanation:

Initial Velocity = 12m/sec

time = 36 s

Final Velocity 0 m/sec (ball comes to stop)

Acceleration= ?

The formula used to find acceleration is:

$Acceleration=\frac{Final\,\,Velocity-Initial\,\,Velocity}{Time}$

Putting values and finding acceleration:

$Acceleration=\frac{Final\,\,Velocity-Initial\,\,Velocity}{Time}$

$Acceleration=\frac{0-12}{36}$

$Acceleration=\frac{-12}{36}$

$Acceleration=\frac{-1}{3}\,\,m/sec^2$

So, acceleration of ball is $\frac{-1}{3}\,\,m/sec^2$

Keywords: Acceleration

Learn more about Acceleration at:

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Feliz [49]

Answer:

Step-by-step explanation:

there are 15 sixteenths in 15/16, how you figure this out is the numerator tells you how many are in the fraction, in this case the numerator says 15, so there are 15, sixteenths in, 15/16

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3 years ago

Any help would be appreciated! :)

ikadub [295]

Answer:

-7, then -13, then -19

Step-by-step explanation:

Plug in x values to get y.

y = -2(0) - 7

y = 0 - 7

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2 years ago

Read 2 more answers

Solve the following systems of equations 2a+4b+c=5 ; a-4b=-6 ; 2b+c=7.

SOVA2 [1]

Answer:

a = -2

b = 1

c = 5

Step-by-step explanation:

Given:

2a + 4b + c = 5 ............(1)

a - 4b = - 6

a = 4b - 6 .............(2)

2b + c = 7

c = 7 - 2b ...........(3)

substituting 2 and 3 in 1, we get

2(4b - 6 ) + 4b + (7 - 2b) = 5

8b - 12 + 4b + 7 - 2b = 5

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b = 1

substituting b in 2, we get

a = 4(1) - 6

a = -2

substituting b in 3, we get

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thus,

a = -2

b = 1

c = 5

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3 years ago

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Gemiola [76]

Answer:

Step-by-step explanation:

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2 years ago

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Galina-37 [17]

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