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Vlad [161]
3 years ago
10

An army depot that overhauls ground mobile radar systems is interested in improving its processes. One problem involves troubles

hooting a particular component that has a high failure rate after it has been repaired and reinstalled in the system. The shop floor supervisor believes that having standard work procedures in place will reduce the time required for troubleshooting this component. Time (in minutes) required troubleshooting this component without and with the standard work procedure is recorded for a sample of 19 employees. In order to determine if having a standard work procedure in place reduces troubleshooting time, they should use
a. a one-tailed paired t-test.
b. a two-tailed test of two independent means.
c. a one-tailed test of two independent means.
d. a two-tailed paired t-test.
e. a test of two proportions.
Mathematics
1 answer:
jok3333 [9.3K]3 years ago
3 0

Answer:

A. a one-tailed paired t-test.

Step-by-step explanation:

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Anthony has the equations of three lines: A,B and C. When he solves a system with equations A and B , he gets no solution. When
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T= u+v/2 for u<br><br> •u= 2t+v<br> •u= 2t/v<br> •u= 2(t-v)<br> •u= 2t-v
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Step-by-step explanation:

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3 0
3 years ago
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A machine making computer chips isn't working correctly, and 5% of the computer chips it makes are defective. If an inspector ch
Rainbow [258]

Answer:

0.25% probability that they are both defective

Step-by-step explanation:

For each computer chip, there are only two possible outcomes. Either they are defective, or they are not. The probability of a computer chip being defective is independent of other chips. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5% of the computer chips it makes are defective.

This means that p = 0.05

If an inspector chooses two computer chips randomly (meaning they are independent from each other), what is the probability that they are both defective?

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.05)^{2}.(0.95)^{0} = 0.0025

0.25% probability that they are both defective

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3 years ago
Can someone really help me please
Aloiza [94]

Answer:

a

Step-by-step explanation:

3 0
3 years ago
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