An example of a non-linear equation would be something like
![x^{2} +2x+1](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%2B2x%2B1)
which is a parabola.
Anything where there is an X with an exponent higher than 1 in a non-linear equation.
J = 94x
example: 25 is your seconds so now you need to find the relationship to get to the 2,350. You could divide 2,350 and 25 and you would get the outcome of 94 .
Answer: " 6.758 * 10³ " .
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The square root of two is irrational. It means that you can't write it as a fraction:
![\sqrt{2} \neq \cfrac{p}{q}\quad\forall p \in \mathbb{Z},\ q \in \mathbb{Z}\setminus\{0\}](https://tex.z-dn.net/?f=%20%5Csqrt%7B2%7D%20%5Cneq%20%5Ccfrac%7Bp%7D%7Bq%7D%5Cquad%5Cforall%20p%20%5Cin%20%5Cmathbb%7BZ%7D%2C%5C%20q%20%5Cin%20%5Cmathbb%7BZ%7D%5Csetminus%5C%7B0%5C%7D%20)
Here's a proof. Assume that you could write
![\sqrt{2} = \cfrac{p}{q}](https://tex.z-dn.net/?f=%20%20%5Csqrt%7B2%7D%20%3D%20%5Ccfrac%7Bp%7D%7Bq%7D%20)
for some integers p and q, and that p and q have no common divisors. If you square both sides you have
![2 = \cfrac{p^2}{q^2} \implies p^2 = 2q^2](https://tex.z-dn.net/?f=%202%20%3D%20%5Ccfrac%7Bp%5E2%7D%7Bq%5E2%7D%20%5Cimplies%20p%5E2%20%3D%202q%5E2%20)
So,
is even, which means that also p is even, and thus there exists some number k such that
. The expression becomes
![p^2 = 2q^2 \implies 4k^2 = 2q^2 \iff q^2 = 2k^2](https://tex.z-dn.net/?f=%20p%5E2%20%3D%202q%5E2%20%5Cimplies%204k%5E2%20%3D%202q%5E2%20%5Ciff%20q%5E2%20%3D%202k%5E2%20)
So, also
is even, and thus q is also even.
But then, p and q are both even, whereas we assumed that they had no common divisors. Contraddiction.
As for the value, any calculator will give you an approximation that starts with
![\sqrt{2} = 1.4142\ldots](https://tex.z-dn.net/?f=%20%5Csqrt%7B2%7D%20%3D%201.4142%5Cldots%20)
so, it is best approximated by 1.4.