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madreJ [45]
3 years ago
5

The length of each side of a square is 6 feet more than the length of a side of a regular Octagon. The perimeter of the square i

s equal to the octagon. Find the length of the square and the length of a side of the octagon.
Please show work, I will give brainliest.
Mathematics
1 answer:
goldfiish [28.3K]3 years ago
8 0

9514 1404 393

Answer:

  • square: 12 ft sides
  • octagon: 6 ft sides

Step-by-step explanation:

This problem can be worked in your head.

If the perimeters of the square and regular octagon are the same, the side length of the 4-sided square must be the same as the length of 2 sides of the 8-sided octagon. Since the side of the square is 6 ft more than the side of the octagon, each side of the octagon must be 6 ft, and each side of the square must be 12 ft.

__

We can let s represent the side length of the octagon. Then we have ...

  8s = perimeter of octagon

  4(s +6) = perimeter of square

These are equal, so ...

  4(s +6) = 8s

  s +6 = 2s . . . . . . divide by 4

  6 = s . . . . . . . . . . subtract s

The octagon has 6-ft sides; the square has 12-ft sides.

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DiKsa [7]

Answer:

2(n-6)=12

(I went too far in my explanation; I'm not going to erase it because I think it is important to have an example on solving these)

Step-by-step explanation:

Twice the difference of a number and 6 is the same as 12.

Twice means 2 times

Difference means the result of subtracting something.

is the same as means equal to (=).

So we are given 2(n-6)=12.

You can start by dividing 2 on both sides are distributing 2 to terms in the ( ).

I will do it both ways and you can pick your favorite.

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