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elena55 [62]
3 years ago
7

Rewrite the following quadratic functions in intercept or factored form. Show your work.

Mathematics
2 answers:
Mariulka [41]3 years ago
4 0

<u>Answer:</u>

y = 5x (x+2)

<u>Step-by-step explanation:</u>

We are given the following the quadratic function and we are to rewrite it in intercept or factored form:

y = 5x^2 + 10x

We can factorize the given expression so taking the common factors out of it to get:

y=5x^2 + 10x

y = 5x (x + 2)

Therefore, the factored form of the given quadratic function is y = 5x (x+2).

Inga [223]3 years ago
3 0

Answer:

y = 5x(x+2)

Step-by-step explanation:

Given quadratic equation is:

y = 5x²+10x

We have to transform given function into factored form.

Taking x common from given function,we get

y = x(5x+10)

5 and 10 are multiple of 5.

Hence,

taking 5 as common,we get

y = x(5)(x+2)

y = 5x(x+2) is factored form of given quadratic function.

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Answer:

y = 11 1/2

Step-by-step explanation:

7y - 63 = y + 3

-y.           -7

6y - 63 = 3

+ 63.     + 63

6y = 69

/6.     /6

y = 11 1/2

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2 years ago
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Choose the expressions that are perfect cubes
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Answer: the second fifth and sixth one

Step-by-step explanation:

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3 years ago
Two opposite sides of a rectangle are each of length x. If the perimeter of the rectangle is 12, then the area, as a function of
Reil [10]

Answer: x(6-x)

Step-by-step explanation:

Given : Two opposite sides of a rectangle are each of length x.

Let the other adjacent side be y.

The perimeter of the rectangle is 12 units.

Perimeter of rectangle is given by :-

P=2(\text{Sum of adjacent sides})\\\\\Rightarrow\ 12=2(x+y)\\\\\Rightarrow\ x+y=\dfrac{12}{2}=6\\\\\Rightarriow\ y=6-x

The area of rectangle is given by :-

A=\text{product of two adjacent sides}\\\\\Rightarrow\ A=xy=x(6-x)

Hence, the area as a function x = x(6-x)

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Domesticated animals were primarily valued for meat.<br> true or false
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Step-by-step explanation:

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a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you
aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that P(A) = 0.8

If you have passed subject A, the probability of passing subject B is 0.8.

This means that P(B|A) = 0.8

Find the probability that the student passes both subjects?

This is P(A \cap B). So

P(B|A) = \frac{P(A \cap B)}{P(A)}

P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

p = P(A) + P(B) - P(A \cap B)

Considering P(B) = 0.7, we have that:

p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86

0.86 = 86% probability that the student passes at least one of the two subjects

3 0
3 years ago
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