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weeeeeb [17]
3 years ago
7

Divide, if possible, and check. If the quotient is undefined, state this -12.6\(-2)

Mathematics
1 answer:
OleMash [197]3 years ago
7 0
The answer is 6.3
-12.6/-2=6.3
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Which values of PP and QQ result in an equation with no solutions? -60x+32=Qx+P−60x+32=Qx+P Choose all answers that apply: Choos
Inga [223]
<h3>Answer:</h3>

  A and C

<h3>Step-by-step explanation:</h3>

Given:

  -60x+32 = Qx+P

Find:

Which values of P and Q result in an equation with no solutions? Choose all answers that apply:

(Choice A) A Q=-60 P=60

(Choice B) B Q=32 P=60

(Choice C) C Q=-60 P=−32

(Choice D) D Q=32 P=−60

Solution:

The equation will have no solution if it reduces to ...

  0 = (non-zero constant)

If we add 60x-32 to both sides, we get

  0 = 60x +Qx + P-32

  0 = (Q+60)x +(P-32)

The x-term must be zero, so Q+60 = 0, or Q = -60.

The constant term must be non-zero, so P-32 ≠0, or P ≠ 32.

The appropriate answer choices are those with Q=-60 and P≠32, A and C.

8 0
3 years ago
Show work please. thank you
Eduardwww [97]
Problem 17, part A

i = simple interest = 900 dolars
p = principle = 1500 dollars
r = interest rate = 0.03 (decimal form of 3%)
t = time in years = unknown (leave it as t for now)

Plug in those values mentioned above and solve for t.

Simple interest formula
i = p*r*t
900 = 1500*0.03*t
900 = 45*t
900/45 = 45*t/45
20 = t
t = 20

Answer: 20 years

=============================================

Problem 17, part B

p = 1500
r = 0.03
t = 5 years

A = p+p*r*t
A = 1500+1500*0.03*5
A = 1500+225
A = 1725

Answer: 1725 dollars

=============================================

Problem 17, part C

Factor out the GCF p, then divide both sides by 1+rt

A = p+p*r*t
A = p*1+p*r*t
A = p*(1+rt)
A/(1+rt) = p*(1+rt)/(1+rt)
A/(1+rt) = p
p = A/(1+rt)

Answer: p = A/(1+rt)

The right side is the fraction of A all over the quantity (1+rt) which may be more readable if written like so 
p = \frac{A}{1+rt}
If you're going to write it in the way p = A/(1+rt) then don't forget to use parenthesis. 

4 0
3 years ago
What number is 7 units to the left of -1?<br><br> 8<br> 6<br> -8<br> -6
Viefleur [7K]

Answer:

7 <u>units to the left is -6 </u>

Step-by-step explanation:

your counting back wards but its not a neg. its positive so the answer is 6

4 0
2 years ago
Which of the following data could be graphed using a dot plot? Select all that apply.
Sphinxa [80]

Answer:

Time taken to complete a test.

-Number of cars in a -household.

-Number of siblings

Distance driven to school.

Step-by-step explanation:

Data used for a dot plot is relatively small data set where the values can fall into a number of categories/bins. Dot plots are used for univariate data where the variable is quantitative or categorical

5 0
3 years ago
The monthly sales (in thousands of units) of a seasonal product are approximated by
Elodia [21]
 <span>Don't forget S is measured in thousands of units so you are solving for : 

100 < 74.5 + 43.75Sin(πt/6) 
25.5 < 43.75Sin(πt/6) 
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ASrcSin(πt/6) > 0.62224 radians 
πt/6 > 0.62224 
t > 6 x 0.62224/π = 1.1884 (4dp) 

This initial value occurs when the sine value is increasing and it will reach its maximum value of 1 when Sin(πt/6) = Sinπ/2, that is when t = 3. 
Consequently, monthly sales exceed 100,000 during the period between t = 1.1884 and 4.8116 
[3 - 1.1884 = 1.8116 so the other extreme occurs at 3 + 1.8116] 

Note : on the basis of these calculations, January is 0 ≤ t < 1 : February is 1 ≤ t < 2 :....May is 4 ≤ t < 5 
So the period when sales exceed 100,000 occurs between Feb 6 and May 25 and annually thereafter.</span>
3 0
3 years ago
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