<h3>
Answer:</h3>
A and C
<h3>
Step-by-step explanation:</h3>
Given:
-60x+32 = Qx+P
Find:
Which values of P and Q result in an equation with no solutions? Choose all answers that apply:
(Choice A) A Q=-60 P=60
(Choice B) B Q=32 P=60
(Choice C) C Q=-60 P=−32
(Choice D) D Q=32 P=−60
Solution:
The equation will have no solution if it reduces to ...
0 = (non-zero constant)
If we add 60x-32 to both sides, we get
0 = 60x +Qx + P-32
0 = (Q+60)x +(P-32)
The x-term must be zero, so Q+60 = 0, or Q = -60.
The constant term must be non-zero, so P-32 ≠0, or P ≠ 32.
The appropriate answer choices are those with Q=-60 and P≠32, A and C.
Problem 17, part A
i = simple interest = 900 dolars
p = principle = 1500 dollars
r = interest rate = 0.03 (decimal form of 3%)
t = time in years = unknown (leave it as t for now)
Plug in those values mentioned above and solve for t.
Simple interest formula
i = p*r*t
900 = 1500*0.03*t
900 = 45*t
900/45 = 45*t/45
20 = t
t = 20
Answer: 20 years=============================================
Problem 17, part B
p = 1500
r = 0.03
t = 5 years
A = p+p*r*t
A = 1500+1500*0.03*5
A = 1500+225
A = 1725
Answer: 1725 dollars=============================================
Problem 17, part C
Factor out the GCF p, then divide both sides by 1+rt
A = p+p*r*t
A = p*1+p*r*t
A = p*(1+rt)
A/(1+rt) = p*(1+rt)/(1+rt)
A/(1+rt) = p
p = A/(1+rt)
Answer: p = A/(1+rt)The right side is the fraction of A all over the quantity (1+rt) which may be more readable if written like so

If you're going to write it in the way p = A/(1+rt) then don't forget to use parenthesis.
Answer:
7 <u>units to the left is -6 </u>
Step-by-step explanation:
your counting back wards but its not a neg. its positive so the answer is 6
Answer:
Time taken to complete a test.
-Number of cars in a -household.
-Number of siblings
Distance driven to school.
Step-by-step explanation:
Data used for a dot plot is relatively small data set where the values can fall into a number of categories/bins. Dot plots are used for univariate data where the variable is quantitative or categorical
<span>Don't forget S is measured in thousands of units so you are solving for :
100 < 74.5 + 43.75Sin(πt/6)
25.5 < 43.75Sin(πt/6)
Sin(πt/6) >25.5/43.75 = 0.582857
ASrcSin(πt/6) > 0.62224 radians
πt/6 > 0.62224
t > 6 x 0.62224/π = 1.1884 (4dp)
This initial value occurs when the sine value is increasing and it will reach its maximum value of 1 when Sin(πt/6) = Sinπ/2, that is when t = 3.
Consequently, monthly sales exceed 100,000 during the period between t = 1.1884 and 4.8116
[3 - 1.1884 = 1.8116 so the other extreme occurs at 3 + 1.8116]
Note : on the basis of these calculations, January is 0 ≤ t < 1 : February is 1 ≤ t < 2 :....May is 4 ≤ t < 5
So the period when sales exceed 100,000 occurs between Feb 6 and May 25 and annually thereafter.</span>