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Aleks04 [339]
3 years ago
5

2. Rank the boiling points of methane, methanol, and methanal from lowest to highest. Explain your ranking. (6 points) 3. The lo

ne pair of electrons on the oxygen atom in an ester can form hydrogen bonds in some situations, but esters cannot form hydrogen bonds with each other. How would you expect the boiling point of an ester to compare with that of an alcohol
Chemistry
1 answer:
zlopas [31]3 years ago
6 0

Answer:

(2) Boiling point order: Methanol (highest) > Methanal > Methane (weakest)

(3) Boiling point of alcohol will be higher than ester molecules

Explanation:

(2) Methane is a non-polar molecule. Hence only weakest van der waal inter molecular force is present between methane molecules.

Methanal is polar molecule due to presence of polar aldehyde group. hence weaker dipole-dipole inter molecular force is present between methanal molecules.

Methanol is a polar protic molecule. Hence strongest H-bonding force act between methanol molecules.

The stronger the inter molecular force, the higher will be boiling point.

Boiling point order: Methanol (highest) > Methanal > Methane (weakest)

(3) An alcohol is a polar protic molecule. Hence strongest H-bonding force exist between alcohol molecules.

An ester is  polar molecule. Therefore weaker dipole-dipole inter molecular force is present between ester molecules.

So boiling point of alcohol will be higher than ester molecules.

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A compound has a percent composition of 81.71% C and 18.29% H. What is the empirical formula of this compound?
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Considering the definition of empirical formula, the empirical formula is C₃H₈.

<h3>Definition of empirical formula</h3>

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.

<h3>Empirical formula in this case</h3>

In this case, in first place you know the percent composition:

  • C: 81.71 %
  • H: 18.29%

Assuming a 100 grams sample, the percentages match the grams in the sample. So you have 81.71 grams of carbon and 18.29 grams of hydrogen H.

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

  • C: \frac{81.71 grams}{12\frac{grams}{mole} }= 6.81 moles
  • H:\frac{18.29 grams}{1\frac{grams}{mole} }= 18.29 moles

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

  • C: \frac{6.81 moles}{6.81 moles}= 1
  • H:\frac{18.29 moles}{6.81 moles}= 2.68 ≅ \frac{8}{3}

To express this relationship in the form of simple integers, it is necessary to multiply by a simple number to achieve this:

  • C: 1×3  =3
  • H:≅ \frac{8}{3}×3= 8

Therefore the C: H mole ratio is 3: 8

Finally, the empirical formula is C₃H₈.

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A 60.0 mL sample of 0.250 M NaOH is added to a beaker containing 125 mL of 0.120 M HOCl. Ka for HOCl is 3.5 x 10-8 at 25o C. Fin
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To identify a liquid substance, a student determined its density. Using a graduated cylinder, she measured out a 45-mL sample of
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Answer:

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So upon calculation, if the density of the liquid substance is equal to either of the substances in the choice, it is that substance.

The relationship between density, mass and volume is given as;

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Probable identity = Toulene

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