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tankabanditka [31]
3 years ago
7

A glass is 1 3 full. Then 40cm3 of orange juice is poured in. The glass is now 5 7 full. What is the total volume of the glass?

Mathematics
2 answers:
Lemur [1.5K]3 years ago
5 0

Answer:

23

Step-by-step explanation:

waffaline waffalda,sld

Effectus [21]3 years ago
3 0

Answer:

V= 105cm^3

Step-by-step explanation:

V=volume

(1/3)V+40=(5/7)V

(5/7)V-(1/3)V=40

(15/21)V-(7/21)V=40

(8/21)V=40

(21/8)(8/21)V=(21/8)(40

V=21*5

V=105 cm3

(1/3)(105)=35, 35+40=75, 75/105=15/21=5/7

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Step-by-step explanation:

\sqrt{16}\div \sqrt{11}

\sqrt{16}\times \sqrt{11}\div \sqrt{11}\times \sqrt{11}

4\times \sqrt{11}\div \(11)  answer

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Step-by-step explanation:

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Step-by-step explanation:

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. The cost of 2 pizzas and 1 burger is ₹ 450. Write a linear equation for this situation and draw its graph.​
Akimi4 [234]

Answer:

The linear equation is;

Y = 450 - 2·X

Please find the included graph

Step-by-step explanation:

Whereby we have the following relation;

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The cost of 1 burger = Y

Hence;

450 = Y + 2·X

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Y = 450 - 2·X

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The graph of the linear equation can be plotted using the assumed data as follows;

Y,           X

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4,          442

5,          440

6,          438

7,          436

8,          434

9,          432

10,          430

11,          428

12,          426

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8 0
3 years ago
The following function represents the value of a motorcycle, in dollars, after x years: f(x) = 19,000(0.91)x
Semenov [28]

Answer:

Option C.The decrease in the value of the motorcycle, which is 9%

Step-by-step explanation:

we have a exponential function of the form

f(x)= ab^x

where

a is the initial value

b represents growth or decay factor

If b >1 then it is an exponential growth

if 0<b<1 then it is an exponential decay

In this problem

a=$19,000

b=0.91 -----> it is exponential decay factor

Find the rate of decrease r

b=(1-r)

substitute

0.91=1-r

r=1-0.91=0.09

Convert to percentage

0.09*100=9%

therefore

0.91 represent the decrease in the value of the motorcycle, which is 9%

7 0
3 years ago
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