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Galina-37 [17]
3 years ago
5

Write the equation of the line in slope-intercept form using y=mx+b​

Mathematics
1 answer:
artcher [175]3 years ago
3 0
Answer:
y=2x+0

Explanation:
To find the “b” of this equation you simply see where the line hits the y- intercept , in this case it will be 0. And to find the “m” of this equation you find the rise over run . Hope that helps.
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ludmilkaskok [199]

Answer:

您能再解釋一下嗎,謝謝

Step-by-step explanation:

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4 years ago
1. A claim states that a specific crimes occurs in the given proportions shown in the table for October through March. Use the f
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Answer:

C. 6.683

Step-by-step explanation:

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4 years ago
Match each polynomial expression with its simplification.
Ann [662]
(3x + 2x -2) + (4x - 2x + 8) = 7x + 6

(2x + 5) + ( 7x - 10) + (3x - 4) + (4x -6) = 16x - 15

(4 + 2x3) + (5x3 + 2) = 27

(6x2 + 3x - 8) + ( 2x2 - 5x - 9) = 8x2 - 2x - 17

(4x2 - 9x3 + 2x4) + (8x4 - 3) + (5x3 - 7x2) = 19

(3 - 4x3 +6x4) + (2x4 + 5) + (9x3 - 8x2) = 39

(9x + 7y4) + (5x + 3x2 - 7y4) = 3x2 + 14x

<span>(9x2 - 5y - 12) + (8 - 9x2 + 5y + 4) = 0</span>
4 0
3 years ago
Ellie is driving at a speed of 55 miles per hour. Let h represent the number of hours that Ellie drive at this speed. Write an a
loris [4]
I believe it would be 55 x h.
4 0
3 years ago
Solve the following linear quadratic system of equations algebraically.<br><br> y=^2+3x-2<br> y+3=5x
USPshnik [31]

Answer:

x=1

y=2

Step-by-step explanation:

y=x^2+3x-2 , y+3=5x

Replace all occurrences of y in y+3=5x with x^2+3x-2.

(x^2+3x-2)+3=5x

y=x^2+3x-2

Add -2 and 3.

x^2+3x+1=5x

y=x^2+3x-2

Subtract 5x from both sides of the <u>equation.</u>

x^2+3x+1-5x=0

y=x^2+3x-2

Subtract 5x from 3x.

x^2-2x+1=0

y=x^2+3x-2

Rewrite 1 as 1^2.

x^2-2x+1^2=0

y=x^2+3x-2

Check that the middle <u>term</u> is two times the <u>product</u> of the numbers being squared in the first <u>term</u> and third <u>term</u>.

2x=2 · x · 1

y=x^2+3x-2

Rewrite the <u>polynomial</u>.

x^2-2 · x · 1 + 1^2=0

y=x^2+3x-2

Factor using the <u>perfect square</u>

<u>trinomial</u> rule a^2-2ab+b^2=(a-b)^2,

where a = x and b = 1.

(x-1)^2=0

y=x^2+3x-2

<u>Set</u> the x-1 equal to 0.

x-1=0

y=x^2+3x-2

Add 1 to both sides of the <u>equation</u>.

x=1

y=x^2+3x-2

Replace all occurrences of x in

y=x^2+3x-2 with 1.

y=(1)^2+3(1)-2

x=1

y=2

3 0
3 years ago
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