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Galina-37 [17]
3 years ago
5

Write the equation of the line in slope-intercept form using y=mx+b​

Mathematics
1 answer:
artcher [175]3 years ago
3 0
Answer:
y=2x+0

Explanation:
To find the “b” of this equation you simply see where the line hits the y- intercept , in this case it will be 0. And to find the “m” of this equation you find the rise over run . Hope that helps.
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Solve 2(x-3)=1-5(2-x)
xeze [42]
Your answer is, x=1.
                                Hope this helps.
5 0
3 years ago
(52) Pleaase check ym answer
Alinara [238K]
X = measure of each of the legs
"perimeter is 8 more than 2 times one of the legs" ---> P = 2x+8
P = 28 is the given perimeter

So,
P = 2x+8
28 = 2x+8
2x+8 = 28
2x = 20
x = 10

If x = 10, then the two legs add up to x+x = 10+10 = 20
Leaving P-20 = 28-20 = 8 inches left over for the base

You have the correct answer (choice D, 8 inches) though your steps are a bit confusing at some parts. Such as the part where you wrote 2x = 10 twice. I think I know what you were trying to say. 

4 0
3 years ago
Two boys are throwing a baseball back and forth. The ball is 4 ft above the ground when it leaves one child’s hand with an upwar
AleksandrR [38]
The answer to this question is A, 12. Hope this helps.
3 0
3 years ago
Read 2 more answers
Par for a 9-hole golf course is 36. Jim was 3 under par for the first 5 holes. 4 over par for the next 2 holes, and 2 under par
Neporo4naja [7]

Total the amounts he was over and under:

-3 + 4 -2 = -1

Now add that to the total par:

36 - 1 = 35

His score was a 35

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7B5x-3y%3D-8%7D%20%5Catop%20%7Bxy%3D12%7D%7D%20%5Cright." id="TexFormul
nignag [31]

Answer:

\left \{ {{5x-3y=-8} \atop {xy=12}} \right.\\\\\left \{ {{5x=3y-8} \atop {xy=12}} \right.\\\\\left \{ {{5x=3y-8} \atop {5xy=60}} \right.\\\\\left \{ {{5x=3y-8} \atop {(3y-8)y=60}} \right.\\\\\left \{ {{5x=3y-8} \atop {3y^{2}-8y -60=0}} \right.\\\\\left \{ {{5x=3y-8} \atop {3y^{2}-18y+10y-60 =0}} \right.\\\\\\\left \{ {{5x=3y-8} \atop {3y(y-6)+10(y-6)=0}} \right.\\\\\left \{ {{5x=3y-8} \atop {(3y+10)(y-6)=0}} \right.\\\\

<=> 5x = 3y - 8

     3y + 10 = 0 or y - 6 = 0

<=> 5x = 3y - 8

     y = -10/3 or y = 6

+) with y = -10/3 => 5x = -10 - 8 <=> 5x  = -18 <=> x = -3.6

+) with y = 6 => 5x = 3.6 - 10 = 8 <=> x = 8/5 = 1.6

Step-by-step explanation:

5 0
2 years ago
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