P=2(L+W)
P=364
L=99
sub and find W
364=2(99+W)
divide both sides by 2
182=99+w
subtract 99 from both sides
83=W
w=83ft
Answer:
Maria needs 3 lengths of gutter of finish the shed.
Step-by-step explanation:
We need to calculate the perimeter of the rectangular shed to know how much 5 feet gutter is needed.
The perimeter of the shed is p = 2(l + b) where l = 10ft and b = 9 ft
p = 2(10 + 9) = 2(19) = 38 ft
Now, the perimeter of the shed also equal 23 ft of gutter already installed plus 5x ft gutter where x = number of gutters.
So 23 + 5x = 38
collecting like terms, we have
5x = 38 - 23
5x = 15
dividing through by 5 we have
5x/5 = 15/5
x = 15/5
x = 3
So, Maria needs 3 lengths of gutter of finish the shed.
Answer:
Answer: 1/12
Step-by-step explanation:
2/5x-4=8-3/5x.
We want to tank x out of the denominator by multiplying x on both sides.
2/5-4x=8x-3/5
Now we simplify
-12x=-1
x=1/12
Put x in the equation to check it
Answer:
A
Step-by-step explanation:
The answer is A
Answer:
![f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%5Cfrac%7B1%7D%7B%28x%5E%7B2%7D%2B1%29%5E%7B2%7D%7D%20%2B%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%2B1%7D)
Step-by-step explanation:
we have
![f(x)=x^{2} +\frac{1}{\sqrt[3]{x}}](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%20%2B%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D)
we know that
In the function
The variable of the function f is now the function g(x)
substitute
![f(g(x))=(\frac{1}{x^{2}+1})^{2} +\frac{1}{\sqrt[3]{(\frac{1}{x^{2}+1})}}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%28%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%2B1%7D%29%5E%7B2%7D%20%2B%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7B%28%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%2B1%7D%29%7D%7D)
