ANSWER
The smaller angle is
![y = 36 \degree](https://tex.z-dn.net/?f=y%20%3D%2036%20%5Cdegree)
.EXPLANATION
Let the angles be
![x \: and \: \: y](https://tex.z-dn.net/?f=x%20%5C%3A%20%20and%20%5C%3A%20%20%5C%3A%20y)
where y is the smaller angle.
Since they are supplementary, they will add up to 180°.
This implies that,
![x + y = 180 \degree...(1)](https://tex.z-dn.net/?f=x%20%2B%20y%20%3D%20180%20%5Cdegree...%281%29)
If one angle is 4 times the other, we can then write the following equation,
![x = 4y...(2)](https://tex.z-dn.net/?f=x%20%3D%204y...%282%29)
We put equation (2) into equation (1) to get,
![4y + y = 180 \degree](https://tex.z-dn.net/?f=4y%20%2B%20y%20%3D%20180%20%5Cdegree)
![5y = 180 \degree](https://tex.z-dn.net/?f=5y%20%3D%20180%20%5Cdegree)
We divide through by 5 to obtain,
![y = 36 \degree](https://tex.z-dn.net/?f=y%20%3D%2036%20%5Cdegree)
This implies that,
![x = 4(36)](https://tex.z-dn.net/?f=x%20%3D%204%2836%29)
Answer:
Answer C
Step-by-step explanation:
Just simplify?
Than your answer should be
Answer:
4.55 pounds
Step-by-step explanation:
From the above question , we are told that:
The relationship between the length and weight of certain sea turtles can be approximated by the equation
L = 0.55 W,
where
L is the length in feet
W is the weight in pounds. If a sea turtle is 2.5 feet long, which is closest to its weight?
L = 2.5 feet
Hence,
2.5 = 0.55W
W = 2.5/0.55
W = 4.5454545455 pounds
Approximately, weight of the sea turtle in pounds = 4.55 pounds