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QveST [7]
3 years ago
14

6 times a number is 27 less then the square of that number find the positive soloution

Mathematics
1 answer:
ella [17]3 years ago
5 0

Answer:

9

Step-by-step explanation:

n2-27=6n

Than n (exponet) 2 - 27 - 6n = 0

Now factor (n-9)(n+3)=0

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Roberta makes $9 an hour plus a 12.5% commission selling jewelry. How much does she
rjkz [21]

Answer:

404.5 dollars

Step-by-step explanation:

8x9+(0.875x380)=404.5

4 0
3 years ago
How would you find the slope of the line containing the points P(4, 9) and R(57, 73)?
nydimaria [60]

Answer:

Slope is defined as the difference in the vertical axis divided by the difference in the horizontal axis, going left to right (s = dy/dx).  P has a lesser x co-ordinate, so it will be R - P in this case, giving us (ry - py) / (rx - px):

s = \frac{{\Delta}y}{{\Delta}x}

s = \frac{73 - 9}{57 - 4}

s = 64/53

3 0
2 years ago
Ben had 12 boxes of cookie dough he separated it into four groups
NeTakaya
There'll be three boxes of cookie dough on each row/group.
4 0
3 years ago
Find the value of the question mark
pogonyaev

Answer:

<em>4.88</em>

Step-by-step explanation:

4 0
3 years ago
Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar
oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Fleet of 18 means that N = 18

9 are carrying nuclear weapons, which means that k = 9

9 are destroyed, which means that n = 9

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X \leq 1) = P(X = 0) + P(X = 1)

In which

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021

P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

4 0
3 years ago
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