If the discriminant b^2-4ac is 0, then you have TWO EQUAL, REAL ROOTS.
If you're given the x-intercepts, you can determine the factors of the polynomial as follows: Take -3, change the sign and write (x+3). Take 5, change the sign and write (x-5). Then the eq'n of the parabola is
f(x) = (x+3)(x-5) = x^2 - 2x -15, in which a=1, b = -2 and c= -15.
You can find the x-coordinate of the vertex, which is also the equation of the axis of symmetry, using
x= -b / (2a). Here, x = -(-2) / (2[1]), or x = 1
Find the y-coordinate by subbing 1 for x in the equation above:
y = (1)^2 - 2(1) - 15 = 1 - 2 - 15 = -16
The vertex is at (1, -16) and the equation of the axis of symm. is x = 1.
Answer:
y=-3/5x+6.6
Step-by-step explanation:
formula y2-y1/x2-x1, y-y2=m(x-x2)
-3-0/6-1
-3/5
y-(-3)=-3/5(x-6)
-3/5*x = -3/5x
-3/5*6 = 3.6 (18/5)
3.6 +3
y=-3/5x+6.6
Answer:
y = 2/3x - 3
Step-by-step explanation:
Just rearrange the equation:
2x - 3y = 9
-3y = -2x + 9
y = -2/-3x + 9/-3
y = 2/3x - 3
Are these simultaneous questions or like seperate ones?
Simultaneous:
4x -3(7x-4) = 12
4x - 21x + 12 = 12
-17x = 0
X = 0
Therefore y = -4
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If it's a graph
x int: (3,0)
Y int: (0, -4)
Um idk if that's the answers you wanted but I hope it helped somehow??
