<span>6.5 x 10^6
To answer this question, you need to divide the mass of the sun by the mass of mercury. So
2.13525 x 10^30 / 3.285 x 10^23 = ?
To do the division, divide the mantissas in the normal fashion
2.13525 / 3.285 = 0.65
And subtract the exponents.
30 - 23 = 7
So you get
0.65 x 10^7
Unless the mantissa is zero, the mantissa must be greater than or equal to 0 and less than 10. So multiply the mantissa by 10 and then subtract 1 from the exponent, giving
6.5 x 10^6
So the sun is 6.5 x 10^6 times as massive as mercury.</span>
Answer:
Domain? Do you by chance mean quadrant? If so it's the 3rd quadrant.
Step-by-step explanation:
In the future try to imagine quadrant 1 in the top right and then going counter-clockwise! It'll help!
answer: where is the question?
Given:
x lies in the III quadrant.
To find:
The values of 
.
Solution:
It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.
We know that,
x lies in the III quadrant. So,
Now,
We know that,
Using the trigonometric ratios, we get
Hence, the required values are 
.
Answer:
The formula of area of triangle= ½ base×height
