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3 years ago

Which answer lists these numbers in order from least to greatest? –11.8, 125, 1.63, –3.982, 49.2

1 answer:

3 0

In a and b and C there are negative numbers AFTER positive numbers, so we know they can't be correct. in a list from least to the greatest all the negative numbers would come before the positive numbers.

the correct answer is d.

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WILL PICK BRAINLIEST!!!

SashulF [63]

The answer is B because when yku combine like terms (x) 2/5 + 1/5 you get 3/6. Then when you simplify the equations, you turn -1/4 into -2/8 to match the 5/8. From there you just subtract 2/8 from 5/8 getting 3/8.

4 0

3 years ago

Please answer quick:

Andreas93 [3]

8 I believe if not use the app so socratic

6 0

3 years ago

Read 2 more answers

please help I am so stuck on this! 100 points and brainiest the choices for each question are in the second attachment

77julia77 [94]

Answer:

Step-by-step explanation:

(A) Definition of Supplementary angles

(B) Distributive property

(D) Reflexcive property

(E) Division property of equality

7 0

3 years ago

Read 2 more answers

remy said the table shows a proportional relationship because each distanc went up by 6ftg. Collin said that it was not a propor

sdas [7]

Answer:

remy would be correct

Step-by-step explanation:

3 0

3 years ago

Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are

jasenka [17]

Answer:

The indicated confidence interval for the difference between the two population means is (-1.5159, 7.5159)

Step-by-step explanation:

Let the drying times of type A be the first population and the drying times of type B be the second population. Then

We have small sample sizes $n_{1} = 11$ and $n_{2} = 9$ , besides $\bar{x}_{1} = 71.5$ , $s_{1} = 3.4$ , $\bar{x}_{2} = 68.5$ and $s_{2} = 3.6$ . Therefore, the pooled

estimate is given by

$s_{p}^{2} = \frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(11-1)(3.4)^{2}+(9-1)(3.6)^{2}}{11+9-2} = 12.1822$

The 99% confidence interval for the true mean difference between the mean drying time of type A and the mean drying time of type B is given by

$(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.01/2}s_{p}\sqrt{\frac{1}{11}+\frac{1}{9}}$ , i.e.,

$(71.5-68.5)\pm t_{0.005}(3.4903)\sqrt{\frac{1}{11}+\frac{1}{9}}$

where $t_{0.005}$ is the 0.5th quantile of the t distribution with (11+9-2) = 18 degrees of freedom. So

$3\pm(-2.8784)(3.4903)(0.4495)$ , i.e.,

the indicated confidence interval for the difference between the two population means is (-1.5159, 7.5159)

5 0

3 years ago