Answer:
Step-by-step explanation:
Given the equation y = 2,5x
y is the height of the water
x is the time.
To get the range of values of the height at t = 60s, we will substitute x = 60 into the function
y = 2.5(60)
y = 150 in
Hence the range of the situation is [0, 150].
The domain will be all positive integers i.e xEZ
Let 
. The tangent plane to the surface at (0, 0, 8) is
The gradient is
so the tangent plane's equation is
The normal vector to the plane at (0, 0, 8) is the same as the gradient of the surface at this point, (1, 1, 1). We can get all points along the line containing this vector by scaling the vector by 
, then ensure it passes through (0, 0, 8) by translating the line so that it does. Then the line has parametric equation
or 
, 
, and 
.
(See the attached plot; the given surface is orange, (0, 0, 8) is the black point, the tangent plane is blue, and the red line is the normal at this point)
sides of right angle triangle follows Pythagoras theroem
which states
a^2 +b^2 = c^2
where a , b and c are sides of right angle triangle.
here none of options do not follow this.
so answer is option D
One question at a time, please. I will focus on #16 and ignore #18.
slope: 3/4 line passes thru (-8,2)
Write out y = mx + b. Subst. 2 for y. Subst. -8 for x Subst. (3/4) for m:
2 = (3/4)(-8) + b. Find b. 2 = -6 + b => b = 8
So your equation is y = (3/4)x + 8. Please, use ( ) around those fractions!
Answer:
D (3,1)
Step-by-step explanation:
solving simultaneous equations
Arrange equations
2x+y=7
3x-4y=5
make y side cancell by addition by multiplying by 4 and 1 as shown
4{2x+y=7}
1{3x-4y=5}
8x+4y=28
3x-4y=5
11x=33
x=33/11=3
substitute for x=3 in 3x-4y=5
9-4y=5
4=4y
y=1
