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lbvjy [14]
4 years ago
7

Katherine has $140 in the bank and is saving $6 per week. Abbie has $462 in the bank, but is spending at a rate of $10 per week.

Which equation will determine when they will have the same amount of money in the bank?
Mathematics
2 answers:
ivanzaharov [21]4 years ago
8 0
Katherine=140+6x
Abbie= 462-10x
Delicious77 [7]4 years ago
3 0

Answer:

thank you

Step-by-step explanation:

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The range of y= 2/3 sin x for pi < x < 3pi/2 is ___?
victus00 [196]

Answer:

-2/3 < y < 0

Step-by-step explanation:

y = Asin(x)

Edit*

There's a node (y=0) at pi for sine wave. At 3/2pi will be the min. So range goes from -2/3 to 0

5 0
3 years ago
Helppppppppppppppppppppppppp
Akimi4 [234]
1. x <= 31
2. x < 28

For number 1, x is less than or equal to 31 because the number of days in a month (represented by x) will be less than or equal to 31.

For number 2, x is less than 28 because the number of students (represented by x) in each class will always be less than 28.
7 0
3 years ago
The sales of a grocery store had an average of $8,000 per day. The store introduced several advertising campaigns in order to in
oksano4ka [1.4K]

Answer:

Null hypothesis:\mu \leq 8000  

Alternative hypothesis:\mu > 8000  

z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2  

p_v =P(Z>2)=0.0228  

Step-by-step explanation:

1) Data given and notation  

\bar X=8300 represent the sample mean  

\sigma=1200 represent the population standard deviation  

n=64 sample size  

\mu_o =800 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 8000, the system of hypothesis are :  

Null hypothesis:\mu \leq 8000  

Alternative hypothesis:\mu > 8000  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2  

4) P-value  

Since is a one-side upper test the p value would given by:  

p_v =P(Z>2)=0.0228  

5) Conclusion  

If we compare the p value and the significance level assumed, for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly higher than $8000.  

4 0
3 years ago
The infant mortality rate is defined as the number of infant deaths per 1,000 live births. This rate is often used as an indicato
Basile [38]

(a)

Q1, the first quartile, 25th percentile, is greater than or equal to 1/4 of the points.  It's in the first bar so we can estimate Q1=5.   In reality the bar includes values from 0 to 9 or 10  (not clear which) and has around 37% of the points so we might estimate Q1 a bit higher as it's 2/3 of the points, say Q1=7.

The median is bigger than half the points.  First bar is 37%, next is 22%, so its about halfway in the second bar, median=15

Third bar is 11%, so 70% so far.  Four bar is 5%, so we're at the right end of the fourth bar for Q3, the third quartile, 75th percentile, say Q3=40

b

When the data is heavily skewed left like it is here, the median tends to be lower than the mean.  The 5% of the data from 80 to 120 averages around 100 so adds 5 to the mean, and 8% of the data from the 60 to 80 adds another 5.6, 15% of the data from 40 to 60 adds about 7.5, plus the rest, so the mean is gonna be way bigger than the median of around 15.

8 0
3 years ago
Very easy question please help I cant do basic math ​
Tom [10]
Sonic sick duck duck
3 0
3 years ago
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