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puteri [66]
2 years ago
13

Please help me how to multiply

Mathematics
2 answers:
Elena-2011 [213]2 years ago
8 0
You got 81-36i because you simply squared each term individual. However, in order to square the term, you must multiply the terms like this: (9-6i)(9-6i)

To multiply these terms, you use a process called FOILing. The letters stand for first, outer, inner, last, referring to the parts of the equation that you multiply. After you multiply all four times, you add the terms. You do so as following;

First: the first terms in both parts. 9 x 9 = 81
Outer: the first term in the first section, and the second term in the second. 9 x -6i = -54i
Inner: the second term in the first section, and the first term in the second. -6i x 9 = -54i
Last: the second term in both parts. -6i x -6i = 36i^2. In math, i = the square root of -1, so i^2 is -1. multiply 36 by -1 and you get -36.

After all the multiplication, you get: 81-54i-54i-36. After combining like terms, you finish with 45-108i.
Travka [436]2 years ago
7 0
Use:(a-b)^2=a^2-2ab+b^2\\-------------------------------\\\\(9-6i)^2=9^2-2\cdot9\cdot6i+(6i)^2=81-108i+36i^2\\\\=81-108i+36(-1)=81-108i-36=45-108i\\\\-------------------------------\\\\i=\sqrt{-1}\to i^2=1
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to determine whether the inverse of a function is a function you can perform the horizontal line test, true or false
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3 years ago
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goblinko [34]
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8 0
3 years ago
2/3 (x + 7) = 10 A) 22 B) 8 C)- 1 3 D 41 3 help me quick plz
otez555 [7]

Answer:

D

Step-by-step explanation:

D BECAUSE IT IS D

4 0
3 years ago
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PSYCHO15rus [73]
Hello!

It tells you what to do in the question

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5 0
3 years ago
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If p = .8 and n = 50, then we can conclude that the sampling distribution of pˆ is approximately a normal distribution
FrozenT [24]

Answer:

Yes we can conclude.

Step-by-step explanation:

The sampling distribution of \hat{p} can be approximated as a Normal Distribution only if:

np and nq are both equal to or greater than 10. i.e.

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  • nq ≥ 10

Both of these conditions must be met in order to approximate the sampling distribution of \hat{p} as Normal Distribution.

From the given data:

n = 50

p = 0.80

q = 1 - p = 1 - 0.80 = 0.20

np = 50(0.80) = 40

nq = 50(0.20) = 10

This  means the conditions that np and nq must be equal to or greater than 10 is being satisfied. So, we can conclude that the sampling distribution of pˆ is approximately a normal distribution

6 0
3 years ago
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