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Jobisdone [24]
4 years ago
9

Find the sum 5 + (-5) + 39

Mathematics
1 answer:
Varvara68 [4.7K]4 years ago
8 0

Hello,

Solution:

Follow PEMDAS

= 5 + (-5) + 39

= 5 - 5 + 39

= 0 + 39

= 39

Answer - 39

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Help will mark Brainliest for the answer
Fiesta28 [93]

Answer:

3rd step

Step-by-step explanation:

2*3+3 is not equal to 2*6 because of bidmas we do multiplication first

8 0
3 years ago
PLEASE HELP RIGHT AWAY!!
Katen [24]

Answer:

$17.35/h

Step-by-step explanation:

In order to get the amount per hour he made, you first need to calculate the global amount of money he made.

He was paid $2,900 then he had costs of $1,200, that leaves him a net income of $1,700 ($2,900 - $1,200)

Then he worked a total of 98 hours for that money.

A salary is an amount of money expressed by a period of time.  In this case, we'll use hours.

So, Jonah earned $1,700 after 98 hours of work:

S = $1,700 / 98 hours = $17.35/h

5 0
3 years ago
What is the standard form of the ellipse equation
vlabodo [156]

Answer: <em>The correct answer is in the first option.</em>

Step-by-step explanation:

Equation of an Ellipse

\dfrac{x^{2} }{a^{2} } +\dfrac{y^{2} }{b^{2} } =1\\\\25x^{2}  - 150x + 9y^{2}  = 0\\\\\text {Let's \: perform \: the \: transformations:}\\\\\dfrac{25x^{2} }{25 \cdot 9} -\dfrac{150x}{25 \cdot 9} +\dfrac{9y^{2} }{25 \cdot 9} =0\\\\\dfrac{x^{2} }{3^{2} } -\dfrac{6x}{3^{2} } +\dfrac{y^{2} }{5^{2} } =0\\\\\dfrac{x^{2} -6x}{3^{2} } +\dfrac{y^{2} }{5^{2} } +\dfrac{3^{2} }{3^{2} } -\dfrac{3^{2} }{3^{2} } =0\\\\\dfrac{x^{2} -6x+3^{2} }{3^{2} } +\dfrac{y^{2} }{5^{2} } =\dfrac{3^{2} }{3^{2} }

\dfrac{(x-3)^{2} }{3^{2} } +\dfrac{y^{2} }{5^{2} } =1

4 0
3 years ago
Could someone please help me with these two?
nlexa [21]
Hello there!

4³ + 2(3 - 2)

= 64 + 2(1)

= 64 + 2

= 66

The correct answer is option C


The second part*

A variable cubed >>>>> x³

Quotient of some number and three >>> b ÷ 3

Product of an unknown value and three >>>>> 3a

Three less than a variable >>>y - 3

Three more than some number >>>> z + 3


If you have any misunderstanding, please let me know. As always, I am here to help!
8 0
3 years ago
Read 2 more answers
If (y) varies directly with x, and y=3 when x=0.2, what is the value of (y) when x=1?
Luba_88 [7]
_Brainliest if helped!!

since it varies directly, we form an equation ,  
Y =kX  where k is a constant
use the points given to find K ,
3 =0.2k , k = 15

So to get final answer, 

when x = 1 
y  = kx, = 1(15)
y= 15

Hence when x=1,    < y = 15 > 
4 0
3 years ago
Read 2 more answers
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