Question

Find the 3rd term in geometric sequence whose first term is -8 and whose common ratio is 6

Answer 1

Answer:

-288

Step-by-step explanation:

Geometric Sequence is the sequence in which every digit is the same multiplier of its previous digit.

The formula of Geometric Sequence is: $a_{n} = a_{1}(r)^{n-1}$

Here we have given that, a₁ = -8, r = 6

So, for finding the 3rd term, n = 3

∵ $a_{n} = a_{1}(r)^{n-1}$

∴ $a_{3} = -8(6)^{3-1}$

⇒ a₃ = -8 × 36 = -288

Thus, third term is -288.